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# Differentiating wrt x Watch

1. is this the same?

xy=c^2
dy/dx= -c^2x^-2

and xy=c^2
dy/dy= -y/x
2. (Original post by Acrux)
is this the same?

xy=c^2
dy/dx= -c^2x^-2
This is fine.

and xy=c^2
dy/dy= -y/x
This is also fine if you meant dy/dx and not dy/dy.
3. (Original post by Zacken)
This is fine.

This is also fine if you meant dy/dx and not dy/dy.
Yes i meant that.
So either working is fine they both give same gradient
4. (Original post by Acrux)
Yes i meant that.
So either working is fine they both give same gradient
Yeah.
5. (Original post by Zacken)
Yeah.
It might be as well to check the question as it may well say to give dy/dx in terms of x. In which case only one of your answers is fine.
6. (Original post by nerak99)
It might be as well to check the question as it may well say to give dy/dx in terms of x. In which case only one of your answers is fine.
It's most a question of "find the tangent to the parabola y = 4ax at P" in which case, either form doesn't matter.
7. Well I didn't see the OP quote the question or are you just guessing? It could be just a Core 4 implicit differentiation Q1i could it not?
8. what is this ****
9. (Original post by nerak99)
Well I didn't see the OP quote the question or are you just guessing? It could be just a Core 4 implicit differentiation Q1i could it not?
Possibly, but given that the OP asked about FP1 a few hours ago and this is pretty much the equation of a hyperbola, I highly doubt it. Plus I don't think they'd put something about a hyperbola in C4 since it's give those who do FP1 an unfair advantage.
10. Well Hyperbola is not on C4 as such but I think cross-referencing previous posts is, as the lawyers say, "too remote" ,to be a defence against overstating your certainty in your post earlier. <<< a very rare emoticon from me!
11. (Original post by nerak99)
Well Hyperbola is not on C4 as such but I think cross-referencing previous posts is, as the lawyers say, "too remote" ,to be a defence against overstating your certainty in your post earlier. <<< a very rare emoticon from me!
Correct.
Tis FP1.

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