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    Can anyone help with this and please explain the reasoning behind the answer?
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    (Original post by goodwinning)
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    Can anyone help with this and please explain the reasoning behind the answer?
    In the spontaneous reaction E(cell) which is calculated from E(red) - E(ox) mustbe positive.

    The half-cell (electrode) that provides electrons is the most negative of the pair (nost easily oxidised, better reducing agent).

    With these two pieces of information you should be able to answer the question.
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    So since current is flowing from B to A would (2) be the anode and (1) the cathode?


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    (Original post by goodwinning)
    So since current is flowing from B to A would (2) be the anode and (1) the cathode?


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    Oxidation always happens at the anode.
 
 
 
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