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So confused with partial fractions 3 linear factor [one repeated] ??? Watch

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    But isn't it suppose to be..
    A(x+1)(x+1)2 + B(2x+1)(x+1)2 +C(2x+1)(x+1)
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    No. Look at how that step works.

    You're multiplying every term in the top line by (2x + 1)(x + 1)2.

    Look at what that gives you.
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    (Original post by Alexion)
    No. Look at how that step works.

    You're multiplying every term in the top line by (2x + 1)(x + 1)2.

    Look at what that gives you.
    Okay, I get it now! Thanks!!
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    In other words, what you are doing is rather like adding together a quarter and a sixth and using 24 as the common denominator when the "lowest" common denominator would be 12.

    You technique will work but will have a cubic terms in the coefficient matching whose coefficient wil;l then be zero. i.e. you will end up doing more work than you have to.
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    (Original post by nerak99)
    In other words, what you are doing is rather like adding together a quarter and a sixth and using 24 as the common denominator when the "lowest" common denominator would be 12.

    You technique will work but will have a cubic terms in the coefficient matching whose coefficient wil;l then be zero. i.e. you will end up doing more work than you have to.
    I see, thank you!!
 
 
 
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