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# So confused with partial fractions 3 linear factor [one repeated] ??? Watch

1. But isn't it suppose to be..
A(x+1)(x+1)2 + B(2x+1)(x+1)2 +C(2x+1)(x+1)
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2. No. Look at how that step works.

You're multiplying every term in the top line by (2x + 1)(x + 1)2.

Look at what that gives you.
3. (Original post by Alexion)
No. Look at how that step works.

You're multiplying every term in the top line by (2x + 1)(x + 1)2.

Look at what that gives you.
Okay, I get it now! Thanks!!
4. In other words, what you are doing is rather like adding together a quarter and a sixth and using 24 as the common denominator when the "lowest" common denominator would be 12.

You technique will work but will have a cubic terms in the coefficient matching whose coefficient wil;l then be zero. i.e. you will end up doing more work than you have to.
5. (Original post by nerak99)
In other words, what you are doing is rather like adding together a quarter and a sixth and using 24 as the common denominator when the "lowest" common denominator would be 12.

You technique will work but will have a cubic terms in the coefficient matching whose coefficient wil;l then be zero. i.e. you will end up doing more work than you have to.
I see, thank you!!

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