it's the same principle as baryon number, except that it applies separately to electrons, muons and tau. so the leptons (e- and ve) have lepton number +1 and the anti-leptons (e+ and vebar) have lepton number -1.
as for your questions, 3b doesn't seem to correspond since in that paper Q3 is a question on reflection.
5a) i) every line must join to every other line from the 4th level to the 1st level.
namely, 1-4, 1-3, 1-2, 2-3, 2-4, 3-4 ie 6 lines.
ii) longest wavelength corresponds to shortest energy, since E=hf=hc/lambda.
In other words, it's the photon emitted for a transition between the 2 levels which are closest together in the energy level diagram.
6b) Well this is like the question you asked, except at the quark level. so you need to know that
proton = uud
neutron = udd
where u=up quark, and d=down quark.
Therefore, in beta- which is a neutron decaying to a proton, it's actually a down quark decaying to an up quark. Therefore:
d→u+e−+νeˉNice to see the old AQA papers again. I did AQA back in the day. Doesn't look like it's changed. I still have that data sheet on my wall!