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# C2-integration question. watch

1. I can't find the ms for this paper, could you tell me of its correct and if not where I've gone wrong?

Thanks

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2. I think you were supposed to add kx^2 rather than minus it
Also I'm not sure what you've done when using your limits. To integrate between 2 and 0, sub in 0 to your expression and take it away from you result when subbing in 2.
3. (Original post by GMQ)
I think you were supposed to add kx^2 rather than minus it
Also I'm not sure what you've done when using your limits. To integrate between 2 and 0, sub in 0 to your expression and take it away from you result when subbing in 2.
You've confused me, is it not 100/3? That's what I get when I sub in 2.
4. (Original post by Questioness)
Right I don't know how i got that either, looking back at it I got -152/3
yeah try again with +14x^2 you should get 100/3
5. (Original post by GMQ)
yeah try again with +14x^2 you should get 100/3
So where did I go wrong?
6. (Original post by Questioness)
So where did I go wrong?
Ahh sorry I misread the question

You have to find the area under the line PN and then subtract the area under the curve (which is 100/3)

area under PN is 2x24 = 48
area under curve is 100/3
which gives 44/3

Sorry for confusing you
7. (Original post by GMQ)
Ahh sorry I misread the question

You have to find the area under the line PN and then subtract the area under the curve (which is 100/3)

area under PN is 2x24 = 48
area under curve is 100/3
which gives 44/3

Sorry for confusing you
Right okay thanks, I don't know where you got 24. Isn't the line graph y=2. Where X=2
8. (Original post by Questioness)
Right okay thanks, I don't know where you got 24. Isn't the line graph y=2. Where X=2
I got y=24 for x=2, using the original equation in the question
9. (Original post by GMQ)
I got y=24 for x=2, using the original equation in the question
Ahh I think o see were your getting at, shouldn't y=28 since it's the maximum is P and the line touches p?
So it must have the same y value.
10. Okay I don't think I can make it any clearer than this:

The equation for the curve is "y = x^3 - 10x^2 + 28x" (as k = 28)

The x value of point P is 2. Putting in x as 2 in the equation you get: (2)^3 - 10(2)^2 + 28(2)

This is equal to the y value at P, equal to "8 - 40 + 56 = 24"

(Original post by Questioness)
Ahh I think o see were your getting at, shouldn't y=28 since it's the maximum is P and the line touches p?
So it must have the same y value.
11. (Original post by GMQ)
Okay I don't think I can make it any clearer than this:

The equation for the curve is "y = x^3 - 10x^2 + 28x" (as k = 28)

The x value of point P is 2. Putting in x as 2 in the equation you get: (2)^3 - 10(2)^2 + 28(2)

This is equal to the y value at P, equal to "8 - 40 + 56 = 24"
Ahh right. Thanks
12. (Original post by Questioness)
Ahh right. Thanks
If you are still stuck/don't understand, there is no shame in saying so
13. (Original post by Questioness)
I can't find the ms for this paper, could you tell me of its correct and if not where I've gone wrong?

Thanks

Attachment 526669526671

This topic is a nuisance
Which year? And which exam board?
14. (Original post by Questioness)
I can't find the ms for this paper, could you tell me of its correct and if not where I've gone wrong?

Thanks

Attachment 526669526671

This topic is a nuisance
you can do this as a single integral:

∫ 24 - ( x3 - 10x2 + 28x ) dx with limits 0 & 2
15. (Original post by SeanFM)
If you are still stuck/don't understand, there is no shame in saying so
I understand now : ). Probs need to practice this more .
16. (Original post by 04MR17)
Which year? And which exam board?
Edexcel. I don't know what year
17. (Original post by Questioness)
I understand now : ). Probs need to practice this more .
You'll be okay, miss flower
18. (Original post by SeanFM)
You'll be okay, miss flower
'tis my name
Spoiler:
Show
Kind of my inside joke. Not so inside anymore
19. (Original post by Questioness)
'tis my name
Spoiler:
Show
Kind of my inside joke. Not so inside anymore
Oh, as in H...? Nice
20. (Original post by SeanFM)
Oh, as in H...? Nice
That's the one. You can read Japanese?

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