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Log equation, i need help watch

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    logyx = 3
    log3x-log3y = 5

    I have to find exact values for x and y but i don't know where to start
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    From equation 1, y^3=x so sub this into equation 2.
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    (Original post by sabana)
    From equation 1, y^3=x so sub this into equation 2.
    thanks, i think i get it now
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    That would give you log3 (y^3÷y) = 5
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    Then finally remove logs
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    (Original post by confusedlemur99)
    thanks, i think i get it now
    No problem
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    (Original post by sabana)
    Then finally remove logs
    i got Y to be 9*square root of 3
    is that right?
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    (Original post by confusedlemur99)
    i got Y to be 9*square root of 3
    is that right?
    Yes.
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    (Original post by Zacken)
    Yes.
    thanks
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    (Original post by confusedlemur99)
    i got Y to be 9*square root of 3
    is that right?
    Yes
 
 
 
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