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# Log equation, i need help watch

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1. logyx = 3
log3x-log3y = 5

I have to find exact values for x and y but i don't know where to start
2. From equation 1, y^3=x so sub this into equation 2.
3. (Original post by sabana)
From equation 1, y^3=x so sub this into equation 2.
thanks, i think i get it now
4. That would give you log3 (y^3÷y) = 5
5. Then finally remove logs
6. (Original post by confusedlemur99)
thanks, i think i get it now
No problem
7. (Original post by sabana)
Then finally remove logs
i got Y to be 9*square root of 3
is that right?
8. (Original post by confusedlemur99)
i got Y to be 9*square root of 3
is that right?
Yes.
9. (Original post by Zacken)
Yes.
thanks
10. (Original post by confusedlemur99)
i got Y to be 9*square root of 3
is that right?
Yes

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