Maths Help Watch

ithinkitslily
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i'm working through some further maths questions and i really don't get how you can find both x and y from this, can anyone help?

so the question asks to work out the values of x and y such that:
(√3+5)(√3+4) = x + y√3

i can get as far as expanding it to 23 + 9√3 = x + y√3
but i don't know how to find x or y without knowing one of the values.
am i supposed to give y in terms of x, and vice versa, or get a number/surd as an answer?
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Zacken
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(Original post by ithinkitslily)
i'm working through some further maths questions and i really don't get how you can find both x and y from this, can anyone help?

so the question asks to work out the values of x and y such that:
(√3+5)(√3+4) = x + y√3

i can get as far as expanding it to 23 + 9√3 = x + y√3
but i don't know how to find x or y without knowing one of the values.
am i supposed to give y in terms of x, and vice versa, or get a number/surd as an answer?
Compare the "surd" and "non-surd" parts.

So if 23 + 9\sqrt{3} = x + y\sqrt{3} then x = 23 and y = 9.
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ithinkitslily
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(Original post by Zacken)
Compare the "surd" and "non-surd" parts.

So if 23 + 9\sqrt{3} = x + y\sqrt{3} then 23 = x and y = 9.
omg that's much simpler than i expected lol
thank you !!
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Zacken
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Also, please try and post maths queries on the maths forum in the future.
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Zacken
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(Original post by ithinkitslily)
omg that's much simpler than i expected lol
thank you !!
You're welcome.
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XxKingSniprxX
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(Original post by Zacken)
Compare the "surd" and "non-surd" parts.

So if 23 + 9\sqrt{3} = x + y\sqrt{3} then x = 23 and y = 9.
When Zacken got there before you did.

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Zacken
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(Original post by XxKingSniprxX)
When Zacken got there before you did.
:rofl:
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