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# How would you rearrange this expression Watch

1. 20 - 1/4λK^(1/2)L^(-3/4)

I need to make λ the subject

My approach would be

20 = 1/4λK^(1/2)L^(-3/4)

80= λK^(1/2)L^(-3/4)

Multiply both sides by K^-(1/2), as I am aiming to get K^0 on the RHS

80K^-(1/2) = λL^(-3/4)

multiply both sides by L^3/4 as I am aiming to get L^0 on the RHS

80K^-(1/2)L^(-3/4) = λ

Is this the correct approach ?
2. (Original post by jon2016)
20 - 1/4λK^(1/2)L^(-3/4)
I'm assuming you meant to set that entire expression equal to 0?

i need to make λ the subject

My approach would be

20 = 1/4λK^(1/2)L^(-3/4)

80= λK^(1/2)L^(-3/4)

Multiply both sides by K^-(1/2), as I am aiming to get K^0 on the RHS

80K^-(1/2) = λL^(-3/4)

multiply both sides by L^3/4 as I am aiming to get L^0 on the RHS

80K^-(1/2)L^(-3/4) = λ

Is this the correct approach ?
Yep.
3. What ever you do on one side you do to the other

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