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    Why is my answer to Q1 d) ii) wrong? I understand the method in the answers, which relies on d) i), but I don't see what I've done wrong
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    (Original post by pippabethan)
    Why is my answer to Q1 d) ii) wrong? I understand the method in the answers, which relies on d) i), but I don't see what I've done wrong
    [Meh]
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    (Original post by pippabethan)
    Why is my answer to Q1 d) ii) wrong? I understand the method in the answers, which relies on d) i), but I don't see what I've done wrong
    Can't see anything wrong with your working, other than in the bottom right you should have \mu = -\frac{22}{87}. Note the minus sign. And follow through with that.
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    (Original post by Zacken)
    How did you get that equation for OX? C does not lie on the line OX, hence it's wrong for you to say OX = OC + whatever. The line OX is quite literally the line passing through both O and X, and C clearly doesn't lie on that line. (Unless X is C, of course - but it isn't).
    X looks to be a general point on CD.

    \vec{OX}=\vec{OC}+\vec{CX}

    Then,

    \vec{OX}=\vec{OC}+\mu\vec{CD}
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    (Original post by pippabethan)
    Why is my answer to Q1 d) ii) wrong? I understand the method in the answers, which relies on d) i), but I don't see what I've done wrong
    Part (d) requires ordinary trigonometry
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    (Original post by ghostwalker)
    X looks to be a general point on CD.

    \vec{OX}=\vec{OC}+\vec{CX}

    Then,

    \vec{OX}=\vec{OC}+\mu\vec{CD}
    Darn, you're right. That was a dumb move on my part, thanks for clearing it up. Will delete my post to avoid confusion.
 
 
 
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