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    Prove that

    Sin THETA - Sin^3THETA / Cos^3 THETA = Tan THETA

    I assume you use the rule that Sin THETA / Cos THETA = Tan THETA but apart from that I'm stuck
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    So Sin theta and sin^3 theta are both over cos^3 theta or just sin^3 theta/cos^3 theta?
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    (Original post by Xzerzes)
    So Sin theta and sin^3 theta are both over cos^3 theta or just sin^3 theta/cos^3 theta?
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     \displaystyle \frac{\sin x(1-\sin^2 x)}{\cos^3 x} .
    Remember that  \sin^2 x + \cos^2 x \equiv 1 .
 
 
 
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