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    Solve 7(k-3)=3k-5

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    (Original post by EleanorS14)
    Solve 7(k-3)=3k-5

    Thanks
    What have you tried?

    Try expanding the LHS first:

    7(k-3) = 7k - 21

    So we have 7(k-3) = 3k-5 \iff 7k - 21 = 3k - 5

    Now put all the k's one one side and all the constants on the other.
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    Thanks
    Would it be like this 7-21 = 3 - 5
    -14=-2
    (Sorry I'm really bad at maths.)
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    (Original post by Zacken)
    What have you tried?

    Try expanding the LHS first:

    7(k-3) = 7k - 21

    So we have 7(k-3) = 3k-5 \iff 7k - 21 = 3k - 5

    Now put all the k's one one side and all the constants on the other.
    Thanks Zacken;64488879
    Would it be like this 7-21 = 3 - 5
    -14=-2
    (Sorry I'm really bad at maths.)
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    (Original post by EleanorS14)
    Solve 7(k-3)=3k-5

    Thanks
    Um, first expand the brackets

    7k-21= 3k-5

    Then collect the like terms together

    7k-3k=-5+21

    Then simplify
    4k=16
    k=16/4
    k=4

    hope it helps
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    (Original post by rohit301099)
    Um, first expand the brackets

    7k-21= 3k-5

    Then collect the like terms together

    7k-3k=-5+21

    Then simplify
    4k=16
    k=16/4
    k=4

    hope it helps
    Thankyou.I understand now.
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    (Original post by EleanorS14)
    Thankyou.I understand now.
    Glad it's sorted now.
 
 
 
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