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    I don't know where else to post this


    From measurements taken on the variation of pressure with depth in a liquid, it was found that, on a certain day, 2m below the surface of a given liquid, the absolute pressure was 1.17 x 105N/m2, while at a depth of 5m the absolute pressure was 142kN/m2. Find a) the relative density of the liquid


    what formula can i use
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    (Original post by cushticwarrior)
    I don't know where else to post this


    From measurements taken on the variation of pressure with depth in a liquid, it was found that, on a certain day, 2m below the surface of a given liquid, the absolute pressure was 1.17 x 105N/m2, while at a depth of 5m the absolute pressure was 142kN/m2. Find a) the relative density of the liquid


    what formula can i use
     P=\rho gh
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    (Original post by langlitz)
     P=\rho gh
    I have tried this already.

    1x10^5/(9.81*2)=5963 This is not the answer given. Do you know what I am doing wrong
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    (Original post by cushticwarrior)
    I have tried this already.

    1x10^5/(9.81*2)=5963 This is not the answer given. Do you know what I am doing wrong
    What's the given answer?
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    (Original post by langlitz)
    What's the given answer?
    0.8 something, relative density.
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    (Original post by cushticwarrior)
    0.8 something, relative density.
    You need to use the difference in pressure and the difference in height: ΔP = ρgΔh
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    Thank you!
 
 
 
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