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    Hi,

    I have tried to solve this question but keep getting the wrong answer- I get 2loga3x^2 whilst the answer is loga9x^4

    Can someone explain what I am doing wrong? Here is the question:

    Write as a single logarithm: 2loga(3x) + logax2
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    (Original post by Logolept)
    Hi,

    I have tried to solve this question but keep getting the wrong answer- I get 2loga3x^2 whilst the answer is loga9x^4

    Can someone explain what I am doing wrong? Here is the question:

    Write as a single logarithm: 2loga(3x) + logax2
    is x2 an xsquared, or just simply 2x?
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    When you multiply indices, you add.
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    (Original post by Logolept)
    Hi,

    I have tried to solve this question but keep getting the wrong answer- I get 2loga3x^2 whilst the answer is loga9x^4

    Can someone explain what I am doing wrong? Here is the question:

    Write as a single logarithm: 2loga(3x) + logax2
    Your answer it's wrong, it's the same thing.

    2\log_a 3x^2 = \log_a (3x^2)^2 = \log_a (9x^4).
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    (Original post by Zacken)
    Your answer it's wrong, it's the same thing.

    2\log_a 3x^2 = \log_a (3x^2)^2 = \log_a (9x^4).
    Re read what you wrote, an error will transpire evident
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    (Original post by Zacken)
    Your answer it's wrong, it's the same thing.

    2\log_a 3x^2 = \log_a (3x^2)^2 = \log_a (9x^4).
    Thank you, I appreciate it.
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    (Original post by Pablo Picasso)
    Re read what you wrote, an error will transpire evident
    I'm dumb, can you point it out for me?
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    k \log_a x = \log_a x^k
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    (Original post by TimGB)
    k \log_a x = \log_a x^k
    Thanks
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    (Original post by Zacken)
    I'm dumb, can you point it out for me?
    isn't, not it's
 
 
 
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