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    Have I done this correctly? If not what have I done wrong thanks.
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    (Original post by junayd1998)
    http://prntscr.com/az6jmc

    Have I done this correctly? If not what have I done wrong thanks.
    Unfortunately not! :no: You've found the area contained within the square but outside the circle, but that isn't the shaded area.

    Instead, think about it like this:

    The shaded area is the area of the square (6 * 6) minus the area of the quarter circle.
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    There's the solution. I don't believe you'd have to factorise it at the end, leaving it as it is would be fine.
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    (Original post by Zacken)
    Unfortunately not! :no: You've found the area contained within the square but outside the circle, but that isn't the shaded area.

    Instead, think about it like this:

    The shaded area is the area of the square (6 * 6) minus the area of the quarter circle.
    Yeah iv found the area in the square. Then the area in the circle . Then taken them away to be left with the four parts, one of them being the shaded region so I divided by 4?
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    (Original post by junayd1998)
    Yeah iv found the area in the square. Then the area in the circle . Then taken them away to be left with the four parts, one of them being the shaded region so I divided by 4?
    Well, you could do that, but you haven't done the subtraction properly.

    144 - 36\pi \neq 108\pi. Instead, 144 - 36\pi is as simplified as possible (bar factorisation).
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    (Original post by Zacken)
    Well, you could do that, but you haven't done the subtraction properly.

    144 - 36\pi \neq 108\pi. Instead, 144 - 36\pi is as simplified as possible (bar factorisation).
    huh I'm so done with maths.
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    (Original post by junayd1998)
    huh I'm so done with maths.
    Well, yeah. \pi is just a number and 36\pi is the number 36 multiplied by the number pi.

    Do you think that 5 - (2\times 2) = (5-3) \times 2 = 2\times 2?
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    (Original post by Zacken)
    Well, yeah. \pi is just a number and 36\pi is the number 36 multiplied by the number pi.

    Do you think that 5 - (2\times 2) = (5-3) \times 2 = 2\times 2?
    So could you just leave it as: x = 144-36pi / 4 ?
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    (Original post by junayd1998)
    So could you just leave it as: x = 144-36pi / 4 ?
    Well, simplify it down a bit to x = \frac{144}{4} - \frac{36\pi}{4} = 36 - 9\pi
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    (Original post by Zacken)
    Well, simplify it down a bit to x = \frac{144}{4} - \frac{36\pi}{4} = 36 - 9\pi
    Fair enough yeah i get it now thanks for the help.
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    (Original post by junayd1998)
    Fair enough yeah i get it now thanks for the help.
    Cheers.
 
 
 
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