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# Line integral, vector field Watch

1. Problem is attached.

To do the line integral, I need to find F(r(t)), but I don't understand how to express it. For example I looked at the online notes provided here: http://tutorial.math.lamar.edu/Class...torFields.aspx

I don't understand how F(r(t)) was derived in the first example. I know how to do the rest.

2. (Original post by blah3210)
Problem is attached.

To do the line integral, I need to find F(r(t)), but I don't understand how to express it. For example I looked at the online notes provided here: http://tutorial.math.lamar.edu/Class...torFields.aspx

I don't understand how F(r(t)) was derived in the first example. I know how to do the rest.

Express it as a vector(either in column, row or i, j, k). F is a function taking a 3d vector to a 3d vector. In this case, .

A general point on the line is , so .
3. (Original post by blah3210)
Problem is attached.

To do the line integral, I need to find F(r(t)), but I don't understand how to express it. For example I looked at the online notes provided here: http://tutorial.math.lamar.edu/Class...torFields.aspx

I don't understand how F(r(t)) was derived in the first example. I know how to do the rest.

To find F(r(t)) you need to sub in for each of the components for example if F=(2x,x-y,0) and the path parametrised by r(t)=(x(t),y(t),z(t))=(t,2t,t^2) (for some interval of t) then whenever you see an x you need to sub in for the x component of the path so the 2x of the vector field becomes 2t since x(t)=t. Similarly for the other components and we get F(r(t))=(2t,t-2t,0)=(2t,-t,0).

Hopefully you can see how it works for your example now.

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