Laurent Series help Watch

(Original post by e^x)
Can some1 check if the solution to Q2b is correct? And if it is correct can you explain why?

(Original post by poorform)
Didn't work through it myself explicitly but it seems to be correct.

You basically want to manipulate whatever you have and get it into a form where you can exploit the properties of a geometric series.

Since you are talking about a Laurent series centred at 0 then the 1/z part is in fact the Laurent series for 1/z centred at 0 so you have to do no work there.

The other two parts are just about thinking about what annulus you want your function to converge on and then just manipulating the respective part to do that.

So for example for the second part of the partial fraction on 0<|z|<1 we want to find a Laurent series expansion for -1/(z-1) valid on 0<|z|<1.

One way to do this is to note that by geometric series and this is valid for |z|<1 so it is certainly valid on 0<|z|<1 which is what we wanted. The rest of the question follows the same line the only thing that changes is how you manipulate the fractions to make sure it is valid for the region you want.

You will want something like 1/(1-z) for Laurent series expansions (for things like a<|z|) and something like 1/(1-(1/z)) for things regions like |z|<b.

It turns out that the Laurent series of functions are equal to the Taylor series of functions in some cases. This is the case when you are looking for series' that are defined on an annulus inside the singularity, like above we wanted to find out the laurent series for -1/z-1 inside |z|<1 so it gives in fact the Taylor series at the point (i.e. all the negative coeffiecents are zero)

No idea if that helped at all I may have just been rambling though.

There are some good youtube videos out there and you will need to practise problems to get familiar with it.

(Original post by e^x)
For the example you did that's what I got, but in the solutions I don't get why they have included the other parts as well