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    • Thread Starter
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    Hi there,

    Is there a quick way of solving part b of this question:

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    I can do part a, but not sure how to do part b without sketching out the 2 equations, but the question is only worth 1 mark so I must be missing something obvious.

    thanks,
    Malcolm.
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    Write out the definition of |x+3| for x≥-3 and x<-3...

    Then see if the answers to part (a) work...
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    0<=x

    So does that mean you can reject the -5<x<-3 part from part a, just leaving: -2<x
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    (Original post by Sir_Malc)
    0<=x

    So does that mean you can reject the -5<x<-3 part from part a, just leaving: -2<x
    Yes.
    • Thread Starter
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    Thanks. I didn't realise you could look at it like that to get the correct region.

    Cheers!
 
 
 
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