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# FP3 Watch

1. http://mathsathawthorn.pbworks.com/f/FP3Jun06.pdf
q6a?
This is what i have done below:
r=sinh0
A=1/2 Integral r^2.dtheta
Therefore A=1/2 Integral sinh^2.dtheta
do i use sinh^2x=cosh^2x-1
Or sinh^x =1/2(cosh2x-1).dtheta
Like how am i supposed to know?
2. (Original post by Ayaz789)
http://mathsathawthorn.pbworks.com/f/FP3Jun06.pdf
q6a?
This is what i have done below:
r=sinh0
A=1/2 Integral r^2.dtheta
Therefore A=1/2 Integral sinh^2.dtheta
do i use sinh^2x=cosh^2x-1
Or sinh^x =1/2(cosh2x-1).dtheta
Like how am i supposed to know?
Which one will let you integrate it easily and which one won't?
3. (Original post by Zacken)
Which one will let you integrate it easily and which one won't?
Will they both work first of all? And 1/2 (cosh2x-1)
4. (Original post by Ayaz789)
Will they both work first of all? And 1/2 (cosh2x-1)
I don't see how integrating cosh^2 x is any easier than integrating sinh^2 x...
5. (Original post by Zacken)
I don't see how integrating cosh^2 x is any easier than integrating sinh^2 x...
Huh? Are you agreeing or disagreeing with me?
6. (Original post by Ayaz789)
Huh? Are you agreeing or disagreeing with me?
I agree that you should use 1/2(cosh 2x...). I don't see why you'd consider cosh^2 x - 1 an option though.
7. (Original post by Zacken)
I agree that you should use 1/2(cosh 2x...). I don't see why you'd consider cosh^2 x - 1 an option though.
Yep haha. If i did cosh^2x-1 can you please show me how i would do it?
8. (Original post by Ayaz789)
Yep haha. If i did cosh^2x-1 can you please show me how i would do it?
But that's what I'm saying, doing cosh^2 x - 1 is useless, you don't do it. If you wanted to, you could do cosh^2 x = 1/2(cosh 2x + 1) but... then that was a waste of your time since you might as well have used cosh 2x +... on sinh^2 x right away.
9. (Original post by Zacken)
But that's what I'm saying, doing cosh^2 x - 1 is useless, you don't do it. If you wanted to, you could do cosh^2 x = 1/2(cosh 2x + 1) but... then that was a waste of your time since you might as well have used cosh 2x +... on sinh^2 x right away.
Okay np
10. (Original post by Ayaz789)
Okay np
Okay?
11. (Original post by Zacken)
Okay?
I mean i understand haha
12. (Original post by Ayaz789)
I mean i understand haha
Oh, okay. Great.

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