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    http://mathsathawthorn.pbworks.com/f/FP3Jun06.pdf
    q6a?
    This is what i have done below:
    r=sinh0
    A=1/2 Integral r^2.dtheta
    Therefore A=1/2 Integral sinh^2.dtheta
    do i use sinh^2x=cosh^2x-1
    Or sinh^x =1/2(cosh2x-1).dtheta
    Like how am i supposed to know?
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    (Original post by Ayaz789)
    http://mathsathawthorn.pbworks.com/f/FP3Jun06.pdf
    q6a?
    This is what i have done below:
    r=sinh0
    A=1/2 Integral r^2.dtheta
    Therefore A=1/2 Integral sinh^2.dtheta
    do i use sinh^2x=cosh^2x-1
    Or sinh^x =1/2(cosh2x-1).dtheta
    Like how am i supposed to know?
    Which one will let you integrate it easily and which one won't?
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    (Original post by Zacken)
    Which one will let you integrate it easily and which one won't?
    Will they both work first of all? And 1/2 (cosh2x-1)
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    (Original post by Ayaz789)
    Will they both work first of all? And 1/2 (cosh2x-1)
    I don't see how integrating cosh^2 x is any easier than integrating sinh^2 x...
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    (Original post by Zacken)
    I don't see how integrating cosh^2 x is any easier than integrating sinh^2 x...
    Huh? Are you agreeing or disagreeing with me?
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    (Original post by Ayaz789)
    Huh? Are you agreeing or disagreeing with me?
    I agree that you should use 1/2(cosh 2x...). I don't see why you'd consider cosh^2 x - 1 an option though.
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    (Original post by Zacken)
    I agree that you should use 1/2(cosh 2x...). I don't see why you'd consider cosh^2 x - 1 an option though.
    Yep haha. If i did cosh^2x-1 can you please show me how i would do it?
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    (Original post by Ayaz789)
    Yep haha. If i did cosh^2x-1 can you please show me how i would do it?
    But that's what I'm saying, doing cosh^2 x - 1 is useless, you don't do it. If you wanted to, you could do cosh^2 x = 1/2(cosh 2x + 1) but... then that was a waste of your time since you might as well have used cosh 2x +... on sinh^2 x right away.
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    (Original post by Zacken)
    But that's what I'm saying, doing cosh^2 x - 1 is useless, you don't do it. If you wanted to, you could do cosh^2 x = 1/2(cosh 2x + 1) but... then that was a waste of your time since you might as well have used cosh 2x +... on sinh^2 x right away.
    Okay np
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    (Original post by Ayaz789)
    Okay np
    Okay?
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    (Original post by Zacken)
    Okay?
    I mean i understand haha
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    (Original post by Ayaz789)
    I mean i understand haha
    Oh, okay. Great.
 
 
 
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