Units in linear graph, Quick Q help asap Watch

pleasehelp1
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#1
the unit on y axis is ms^-2, metres per second squared

the unit on x axis is m^2, metres squared

The unit of the gradient will be ???

ms^-2, metres per second squared
or
ms, metres per second
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FirePenguin
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If I'm not wrong, the value of a gradient won't have units.
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pleasehelp1
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Are you sure i thought it had to have some form of unit as both the y and x axis do
I thought the unit of the gradient had to be, delta of the unit of the y axis per delta of the unit of the x axis
for example a velocity over time graph
v=ms^-1
t=s
Therefore unit of gradient is ms^-1 per s = ms^-2

So for my graph im getting confused, as i think the unit of the gradient should be
ms^-2 per m^2 = ?????
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uberteknik
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(Original post by pleasehelp1)
Are you sure i thought it had to have some form of unit as both the y and x axis do
I thought the unit of the gradient had to be, delta of the unit of the y axis per delta of the unit of the x axis
for example a velocity over time graph
v=ms^-1
t=s
Therefore unit of gradient is ms^-1 per s = ms^-2

So for my graph im getting confused, as i think the unit of the gradient should be
ms^-2 per m^2 = ?????
Yes, you do need to quote the units as SI base.

Gradient = y/x

using y = ms-2 and x = m2

converting to SI base to avoid any confusion:

\frac{y}{x} = \frac{LS^{-2}}{L^{2}}

\frac{y}{x} = LS^{-2}L^{-2} = L^{-1}S^{-2}

This looks very much like the SI base units for pressure N/m2 with mass omitted.

i.e. pressure = F/A = \frac{MLS^{-2}}{L^{2}} = ML^{-1}{S^{-2}}
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pleasehelp1
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thanks for the help
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