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    The frequency of sound in an oilbird's click is 2.0 kHz and a click is 2.0 ms in duration.
    Determine whether these clicks can be used to locate obstacles at a distance of 50 cm.
    Speed of sound = 330 m/s (5 marks)

    I take it ms = milli seconds so 2x10^-3

    If so I don't know how right my answer is but I started off working out the wavelength of the click by doing 330/2000= 0.165m (2000=2kHz)
    Then I did 0.165x(2x10^-3) which gives 0.00033m
    So I thought this question would be like a ultrasound one so I said it would not be able to detect objects

    I'm not sure if this is right because the answer is quite small compared to what it's asking to find so yeah
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Updated: May 8, 2016
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