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    The question follows...
    Euporium reacts with dilute sulfuric acid to form a solution of euporium sulfate and hydrogen gas.

    A chemist reacts 0.608g of Euporium (Mr = 152) with an excess of H2SO4 and collects 144 cm3 of H2 gas at room temperature and pressure.

    Analyse the chemist's results to write the overall equation for the reaction between euporium + sulfuric acid.

    This is what I did.
    I know that 1 mol of gas is 24000cm3
    I found out that 144cm3 is equivalent to 0.006 moles of H2.

    Then, I did 0.608 / 152 to get 0.004 moles.

    This meant that Euporium and Hydrogen gas were in the ratio 2:3

    The equation I wrote was 2Eu + H2SO4 -> Eu2So4 + 3H2

    But I am wrong and I don't know where. Please help!
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    (Original post by nwmyname)
    The question follows...
    Euporium reacts with dilute sulfuric acid to form a solution of euporium sulfate and hydrogen gas.

    A chemist reacts 0.608g of Euporium (Mr = 152) with an excess of H2SO4 and collects 144 cm3 of H2 gas at room temperature and pressure.

    Analyse the chemist's results to write the overall equation for the reaction between euporium + sulfuric acid.

    This is what I did.
    I know that 1 mol of gas is 24000cm3
    I found out that 144cm3 is equivalent to 0.006 moles of H2.

    Then, I did 0.608 / 152 to get 0.004 moles.

    This meant that Euporium and Hydrogen gas were in the ratio 2:3

    The equation I wrote was 2Eu + H2SO4 -> Eu2So4 + 3H2

    But I am wrong and I don't know where. Please help!
    Take a look at your equation again, is the equation balanced?
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    (Original post by alfmeister)
    Take a look at your equation again, is the equation balanced?
    I got it don't worry.
 
 
 
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