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    Title says it all, all the stuff online is with a coordinate system.

    I.e, how would I get the CoM for triangle BAD in Q7

    https://c108ac80655dfd1f2bfc8c295d91...%20Edexcel.pdf
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    (Original post by 16characterlimit)
    Title says it all, all the stuff online is with a coordinate system.

    I.e, how would I get the CoM for triangle BAD in Q7

    https://c108ac80655dfd1f2bfc8c295d91...%20Edexcel.pdf
    For a triangle, distance of centre of mass from any side is 1/3 the perpendicular height from that side.

    So, what's the height of BAD?
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    (Original post by ghostwalker)
    For a triangle, distance of centre of mass from any side is 1/3 the perpendicular height from that side.

    So, what's the height of BAD?
    d*sqrt(3), thank you very much.

    What about for the x coordinate.

    And can I do this with scalenes?
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    (Original post by 16characterlimit)
    a, thank you very much.

    What about for the x coordinate.

    And can I do this with scalenes?
    By symmetry, the CofM will be on the line AC, extended if necessary.

    Not sure why you're asking about scalenes as there are none in the question, but the same principle applies 1/3 the perpendicular height.
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    (Original post by ghostwalker)
    By symmetry, the CofM will be on the line AC, extended if necessary.

    Not sure why you're asking about scalenes as there are none in the question, but the same principle applies 1/3 the perpendicular height.
    Just asking so I can use this method for all cases, since it obviously will work for right angled triangles.
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    (Original post by 16characterlimit)
    Just asking so I can use this method for all cases, since it obviously will work for right angled triangles.
    1/3 perpendicular height applies to all lamina triangles.
 
 
 
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