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    The curve with equation y = f(x) passes through the point (−1, 0).
    Given that
    f ′(x) = 12x^2 − 8x + 1,
    find f(x).

    I've used intergration but i dont know where the (-1,0) co-ordinate fits in.
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    (Original post by toad456)
    The curve with equation y = f(x) passes through the point (−1, 0).
    Given that
    f ′(x) = 12x^2 − 8x + 1,
    find f(x).

    I've used intergration but i dont know where the (-1,0) co-ordinate fits in.
    When you integrate f(x) you will get F(x) + C. so you use those co-ordinates to find C.
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    (Original post by zetamcfc)
    When you integrate f(x) you will get F(x) + C. so you use those co-ordinates to find C.
    thx i knew i was missing something.
 
 
 
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