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How did it go?

Was okay upto the last questions where it got very tricky..

Was okay upto the last questions where it got very tricky..

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what the hell was q6 about?

for the 8) part i) question fr proving tan identities how many marks would i lose for working tan60 to be root3/2 instead of root3... i know it was a stupid mistake! But i carried on..

also for part ii) what were the solutions? i think i made it too complicated with tan^4theta etc..

also for part ii) what were the solutions? i think i made it too complicated with tan^4theta etc..

I was aiming for 100%, but sadly that volumes of revolution one tripped me up...anyone manage to do that one? Someone told me it had something to do with "integration by parts"...which I've never heard of.

If I remember correctly (from 5 minutes ago)...

We were supposed to find the volume of the above equation between:

When revolved through 4 right-angles about the X-axis.

I have no idea how to do it using the content of the C3 course!

If I remember correctly (from 5 minutes ago)...

We were supposed to find the volume of the above equation between:

•

f(x)

•

x=1

•

x=e^1

•

y=0

When revolved through 4 right-angles about the X-axis.

I have no idea how to do it using the content of the C3 course!

byebyebye

What draw secx and solve the equation it gave?

maybe it was 5 then. where you had to rearrange an integral to get a=.

epoxi

I was aiming for 100%, but sadly that volumes of revolution one tripped me up...anyone manage to do that one? Someone told me it had something to do with "integration by parts"...which I've never heard of.

If I remember correctly (from 5 minutes ago)...

We were supposed to find the volume of the above equation between:

When revolved through 4 right-angles about the X-axis.

I have no idea how to do it using the content of the C3 course!

If I remember correctly (from 5 minutes ago)...

We were supposed to find the volume of the above equation between:

•

f(x)

•

x=1

•

x=e^1

•

y=0

When revolved through 4 right-angles about the X-axis.

I have no idea how to do it using the content of the C3 course!

for the volume of revo, you do y^2, then you get 4 over blah, which is equal to a sixth of the differentiated value calculated in part one. So its a sixth times the original question i think

byebyebye

Oh right. well you had to integrate using the limits to get an answer with a as an unknown.. then you put it to equal 45 as it said the area = 45.

oh yeah of course. ive never seen that before

PHKnows

for the volume of revo, you do y^2, then you get 4 over blah, which is equal to a sixth of the differentiated value calculated in part one. So its a sixth times the original question i think

So basically you differentiate it instead of integrating (so you can use C3 chain rule etc.)? Damn, I should've thought of that!

byebyebye

Yeah secx is just annoying to draw.. ah well easy 2 marks i guess!

i thought it rearranged to tanx=(some number)??

I Can't remember the question though..

i thought it rearranged to tanx=(some number)??

I Can't remember the question though..

If you're talking about the very last question, then you got:

(tanx)^2=a (where a=something with loads of (k^2)s flying around...which is a positive constant).

then

tanx=a^0.5

because a is positive and real, a^0.5 gives two roots (one positive and one negative) which will cross once each on tanx between 0 and 180.

does anyone know what the grade boundaries would be

PHKnows

for the volume of revo, you do y^2, then you get 4 over blah, which is equal to a sixth of the differentiated value calculated in part one. So its a sixth times the original question i think

i exactly agree with this! took me a while to spot it, but got there in the end

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