# vector

Watch
Announcements
Thread starter 5 years ago
#1
http://prnt.sc/b4b15n

part b) is 3/4b right? could you write just that because that is one of the ways to get from O to P or do you have to write 1/4 a as well because that is another way you could get there.
0
5 years ago
#2
(Original post by junayd1998)
http://prnt.sc/b4b15n

part b) is 3/4b right? could you write just that because that is one of the ways to get from O to P or do you have to write 1/4 a as well because that is another way you could get there.
no matter which route you take, the answer should be the same.
To get from O to P, you could do:
• O to A, then A to P, or
• O to B, then B to P
0
Thread starter 5 years ago
#3
(Original post by surina16)
no matter which route you take, the answer should be the same.
To get from O to P, you could do:
• O to A, then A to P, or
• O to B, then B to P
ugh hate vectors
0
5 years ago
#4
(Original post by junayd1998)
ugh hate vectors
Really? They're one of my favourite bits in maths so far
Do you understand where you went wrong in this question?
0
Thread starter 5 years ago
#5
(Original post by surina16)
Really? They're one of my favourite bits in maths so far
Do you understand where you went wrong in this question?
Yeah, haha; you need to teach me.
0
5 years ago
#6
(Original post by junayd1998)
Yeah, haha; you need to teach me.
lol post any vector questions here if you get stuck and I'm sure everyone will help out
0
Thread starter 5 years ago
#7
(Original post by surina16)
lol post any vector questions here if you get stuck and I'm sure everyone will help out
http://prntscr.com/b4cif7 well I'm stuck on this, this is how far i got what do i do from here
0
5 years ago
#8
(Original post by junayd1998)
http://prntscr.com/b4cif7 well I'm stuck on this, this is how far i got what do i do from here
Ah okay, you've done everything correctly - now all you have to do is simplify it
It's just a case of multiplying out that bracket and adding the terms together.
0
Thread starter 5 years ago
#9
(Original post by surina16)
Ah okay, you've done everything correctly - now all you have to do is simplify it
It's just a case of multiplying out that bracket and adding the terms together.
http://prnt.sc/b4cqtu like that???
0
5 years ago
#10
(Original post by junayd1998)
http://prnt.sc/b4cqtu like that???
Yes

I personally find it easier sometimes to use decimals like:
a - 0.75a + 0.75b but what you did is perfect

Now do you know how to tidy that expression up a little?
(ie. what to do with: a + -3/4a + 3/4b)
0
Thread starter 5 years ago
#11
(Original post by surina16)
Yes

I personally find it easier sometimes to use decimals like:
a - 0.75a + 0.75b but what you did is perfect

Now do you know how to tidy that expression up a little?
(ie. what to do with: a + -3/4a + 3/4b)

http://prntscr.com/b4cu91 that?
0
5 years ago
#12
No, what did you do to get to that?
What you want to do is 1 - 3/4 for the a term and then leave b as it is
0
Thread starter 5 years ago
#13
(Original post by surina16)
No, what did you do to get to that?
What you want to do is 1 - 3/4 for the a term and then leave b as it is
Where does 1 come from ? ugh im confused
1
5 years ago
#14
(Original post by junayd1998)
Where does 1 come from ? ugh im confused
you have the expression:
a + -3/4a + 3/4b

a is the same as 1a, we just don't put the 1 there as it adds no meaning.

I'm guessing we need to go over fractions?

Example 1:
2/3 - 1/6
To add/subtract fractions, you must have a common denominator.
The lowest common multiple of 3 and 6 is 6, so you want the denominator of both fractions to be 6.

2/3 can be written with 6 as the denominator if you multiply the fraction by 2/2 (you are not changing the value as 2/2 is the same as 1)
2 * 2 = 4, 3 * 2 = 6. So you get 4/6.

Now you can subtract the fractions.
4/6 - 1/6 = (4-1)/6 = 3/6 --> you can then simplify this to 1/2.

-------------------------------------------------------------------------------------------
Now can you do 1 - 3/4, and see how this would link to the question?
0
Thread starter 5 years ago
#15
(Original post by surina16)
you have the expression:
a + -3/4a + 3/4b

a is the same as 1a, we just don't put the 1 there as it adds no meaning.

I'm guessing we need to go over fractions?

Example 1:
2/3 - 1/6
To add/subtract fractions, you must have a common denominator.
The lowest common multiple of 3 and 6 is 6, so you want the denominator of both fractions to be 6.

2/3 can be written with 6 as the denominator if you multiply the fraction by 2/2 (you are not changing the value as 2/2 is the same as 1)
2 * 2 = 4, 3 * 2 = 6. So you get 4/6.

Now you can subtract the fractions.
4/6 - 1/6 = (4-1)/6 = 3/6 --> you can then simplify this to 1/2.

-------------------------------------------------------------------------------------------
Now can you do 1 - 3/4, and see how this would link to the question?
Yeah 1/4 lmao but I don't see how it links one bit
0
5 years ago
#16
(Original post by junayd1998)
Yeah 1/4 lmao but I don't see how it links one bit
because you have 1a and you want to subtract 3/4a?
Sorry I'm not very good at explaining and have no idea how else to put it??

1a - 3/4a = 1/4a

add this to the b part and you have:
1/4 + 3/4b
0
Thread starter 5 years ago
#17
(Original post by surina16)
because you have 1a and you want to subtract 3/4a?
Sorry I'm not very good at explaining and have no idea how else to put it??

1a - 3/4a = 1/4a

add this to the b part and you have:
1/4 + 3/4b
I think I get what you mean, I think I was confused because 1a isn't a fraction like its the same as 1/1 - 3/4. I get you now i think . Thanks for your help and explanation appreciate it. Would you mind helping me on a few others? If not, its fine your probably getting sick of me trying to get my head around this.
0
5 years ago
#18
(Original post by surina16)
They're one of my favourite bits in maths so far
1
X

new posts
Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### Poll

Join the discussion

#### Feeling behind at school/college? What is the best thing your teachers could to help you catch up?

Extra compulsory independent learning activities (eg, homework tasks) (12)
7.59%
Run extra compulsory lessons or workshops (27)
17.09%
Focus on making the normal lesson time with them as high quality as possible (26)
16.46%
Focus on making the normal learning resources as high quality/accessible as possible (22)
13.92%
Provide extra optional activities, lessons and/or workshops (44)
27.85%
Assess students, decide who needs extra support and focus on these students (27)
17.09%