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    http://prnt.sc/b4b15n

    part b) is 3/4b right? could you write just that because that is one of the ways to get from O to P or do you have to write 1/4 a as well because that is another way you could get there.
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    (Original post by junayd1998)
    http://prnt.sc/b4b15n

    part b) is 3/4b right? could you write just that because that is one of the ways to get from O to P or do you have to write 1/4 a as well because that is another way you could get there.
    no matter which route you take, the answer should be the same.
    To get from O to P, you could do:
    • O to A, then A to P, or
    • O to B, then B to P
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    (Original post by surina16)
    no matter which route you take, the answer should be the same.
    To get from O to P, you could do:
    • O to A, then A to P, or
    • O to B, then B to P
    ugh hate vectors
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    (Original post by junayd1998)
    ugh hate vectors
    Really? They're one of my favourite bits in maths so far
    Do you understand where you went wrong in this question?
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    (Original post by surina16)
    Really? They're one of my favourite bits in maths so far
    Do you understand where you went wrong in this question?
    Yeah, haha; you need to teach me.
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    (Original post by junayd1998)
    Yeah, haha; you need to teach me.
    lol post any vector questions here if you get stuck and I'm sure everyone will help out
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    (Original post by surina16)
    lol post any vector questions here if you get stuck and I'm sure everyone will help out
    http://prntscr.com/b4cif7 well I'm stuck on this, this is how far i got what do i do from here
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    (Original post by junayd1998)
    http://prntscr.com/b4cif7 well I'm stuck on this, this is how far i got what do i do from here
    Ah okay, you've done everything correctly - now all you have to do is simplify it
    It's just a case of multiplying out that bracket and adding the terms together.
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    (Original post by surina16)
    Ah okay, you've done everything correctly - now all you have to do is simplify it
    It's just a case of multiplying out that bracket and adding the terms together.
    http://prnt.sc/b4cqtu like that???
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    (Original post by junayd1998)
    http://prnt.sc/b4cqtu like that???
    Yes

    I personally find it easier sometimes to use decimals like:
    a - 0.75a + 0.75b but what you did is perfect

    Now do you know how to tidy that expression up a little?
    (ie. what to do with: a + -3/4a + 3/4b)
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    (Original post by surina16)
    Yes

    I personally find it easier sometimes to use decimals like:
    a - 0.75a + 0.75b but what you did is perfect

    Now do you know how to tidy that expression up a little?
    (ie. what to do with: a + -3/4a + 3/4b)


    http://prntscr.com/b4cu91 that?
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    No, what did you do to get to that?
    What you want to do is 1 - 3/4 for the a term and then leave b as it is
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    (Original post by surina16)
    No, what did you do to get to that?
    What you want to do is 1 - 3/4 for the a term and then leave b as it is
    Where does 1 come from ? ugh im confused
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    (Original post by junayd1998)
    Where does 1 come from ? ugh im confused
    you have the expression:
    a + -3/4a + 3/4b

    a is the same as 1a, we just don't put the 1 there as it adds no meaning.

    I'm guessing we need to go over fractions?

    Example 1:
    2/3 - 1/6
    To add/subtract fractions, you must have a common denominator.
    The lowest common multiple of 3 and 6 is 6, so you want the denominator of both fractions to be 6.

    2/3 can be written with 6 as the denominator if you multiply the fraction by 2/2 (you are not changing the value as 2/2 is the same as 1)
    2 * 2 = 4, 3 * 2 = 6. So you get 4/6.

    Now you can subtract the fractions.
    4/6 - 1/6 = (4-1)/6 = 3/6 --> you can then simplify this to 1/2.

    -------------------------------------------------------------------------------------------
    Now can you do 1 - 3/4, and see how this would link to the question?
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    (Original post by surina16)
    you have the expression:
    a + -3/4a + 3/4b

    a is the same as 1a, we just don't put the 1 there as it adds no meaning.

    I'm guessing we need to go over fractions?

    Example 1:
    2/3 - 1/6
    To add/subtract fractions, you must have a common denominator.
    The lowest common multiple of 3 and 6 is 6, so you want the denominator of both fractions to be 6.

    2/3 can be written with 6 as the denominator if you multiply the fraction by 2/2 (you are not changing the value as 2/2 is the same as 1)
    2 * 2 = 4, 3 * 2 = 6. So you get 4/6.

    Now you can subtract the fractions.
    4/6 - 1/6 = (4-1)/6 = 3/6 --> you can then simplify this to 1/2.

    -------------------------------------------------------------------------------------------
    Now can you do 1 - 3/4, and see how this would link to the question?
    Yeah 1/4 lmao but I don't see how it links one bit
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    (Original post by junayd1998)
    Yeah 1/4 lmao but I don't see how it links one bit
    because you have 1a and you want to subtract 3/4a?
    Sorry I'm not very good at explaining and have no idea how else to put it??

    1a - 3/4a = 1/4a

    add this to the b part and you have:
    1/4 + 3/4b
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    (Original post by surina16)
    because you have 1a and you want to subtract 3/4a?
    Sorry I'm not very good at explaining and have no idea how else to put it??

    1a - 3/4a = 1/4a

    add this to the b part and you have:
    1/4 + 3/4b
    I think I get what you mean, I think I was confused because 1a isn't a fraction like its the same as 1/1 - 3/4. I get you now i think . Thanks for your help and explanation appreciate it. Would you mind helping me on a few others? If not, its fine your probably getting sick of me trying to get my head around this.
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    (Original post by surina16)
    They're one of my favourite bits in maths so far
    :five: :nutcase:
 
 
 
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