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    http://www.mei.org.uk/files/papers/c409jn_gegd.pdf

    6ii

    i got the bit where it says sec^2, but i dont understand the integration, can someone give me a step by step
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    Well you have the thing you found the partial fractions for, but it's squared
    So it becomes R^2 x cos(Theta-alpha)^2
    So it's asking for you to integrate 1/R^2 x sec(theta-alpha) which will become 1/R^2 x the integration
    The integration will be tan(theta-alpha) since you're letting (theta-alpha) be equal to x
    Since you're treating the (theta-alpha) as a singular value, it won't have an effect on the integration

    At this point, you substitute the values into theta so you end up with the answer shown

    edit: I should also mention that quite a lot of the integrations/differentiations are in the formula book, so you don't usually have to worry about them, just remember the ones that aren't in there
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    (Original post by liverpool2044)
    http://www.mei.org.uk/files/papers/c409jn_gegd.pdf

    6ii

    i got the bit where it says sec^2, but i dont understand the integration, can someone give me a step by step
    (cosx + sqrt(3)sinx)^2 = (cosx)^2 (1+sqrt(3)tanx))^2 ,so I hope you can see what to do.
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    (Original post by C-rated)
    Well you have the thing you found the partial fractions for, but it's squared
    So it becomes R^2 x cos(Theta-alpha)^2
    So it's asking for you to integrate 1/R^2 x sec(theta-alpha) which will become 1/R^2 x the integration
    The integration will be tan(theta-alpha) since you're letting (theta-alpha) be equal to x
    Since you're treating the (theta-alpha) as a singular value, it won't have an effect on the integration

    At this point, you substitute the values into theta so you end up with the answer shown
    thank you, why is it 1/the answer to previous though?
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    Name:  image.jpg
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Size:  411.2 KBI rushed it so it's messy but using the parts before u should get this
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    (Original post by liverpool2044)
    thank you, why is it 1/the answer to previous though?
    You work out the equivalent of cos theta + sqrt3 sin theta in the first part and that's what's on the bottom of the integral
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    (Original post by liverpool2044)
    thank you, why is it 1/the answer to previous though?
    They asked you to change it into a different form so now they're asking for you to apply that different form to another question to get the answer
 
 
 
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