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    Hey guys,
    does anyone know the sine rule for angles???
    and to add to that
    does anyone know the cosine rule for angles???
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    yes what do you want to know about it?
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    yes, SinA/a = SinB/b, where A is an angle and a is a length of a triangle
    this may help: https://www.youtube.com/watch?v=RL2F49BwQTA

    ~
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    (Original post by chemistry igcse)
    yes what do you want to know about it?
    Sorry for not replying earlier,
    I wanted to know what the equations were
    if you could tell me that would be much appreciated
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    (Original post by Virolite)
    yes, SinA/a = SinB/b, where A is an angle and a is a length of a triangle
    this may help: https://www.youtube.com/watch?v=RL2F49BwQTA

    ~
    Thank you so much,
    you have literally saved me
    because I doing an exam practice paper for my maths revision
    and I was panicking
    I wouldn't call it revision though as Im asking for help
    well that's just me LOL
    thanks again
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    (Original post by AmirahxRashid)
    Thank you so much,
    you have literally saved me
    because I doing an exam practice paper for my maths revision
    and I was panicking
    I wouldn't call it revision though as Im asking for help
    well that's just me LOL
    thanks again
    no worries pal
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    Sine rule for angles is Sin(A)/a=Sin(B)/b
    Cosine rule for angles is Cos(A) =b2 + c2 - a2/2bc Therefore A = Cos-1(b2 + c2 - a2/2bc)
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    (Original post by 34908seikj)
    Sine rule for angles is Sin(A)/a=Sin(B)/b
    Cosine rule for angles is Cos(A) =b2 + c2 - a2/2bc Therefore A = Cos-1(b2 + c2 - a2/2bc)
    Thank you so much
    im guessing u just rearranged the formula right
    thanks
 
 
 
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