AmirahxRashid
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#1
Report Thread starter 6 years ago
#1
Hey guys,
does anyone know the sine rule for angles???
and to add to that
does anyone know the cosine rule for angles???
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chemistry igcse
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#2
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yes what do you want to know about it?
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Virolite
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#3
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yes, SinA/a = SinB/b, where A is an angle and a is a length of a triangle
this may help: https://www.youtube.com/watch?v=RL2F49BwQTA

~
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AmirahxRashid
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#4
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#4
(Original post by chemistry igcse)
yes what do you want to know about it?
Sorry for not replying earlier,
I wanted to know what the equations were
if you could tell me that would be much appreciated
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AmirahxRashid
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#5
Report Thread starter 6 years ago
#5
(Original post by Virolite)
yes, SinA/a = SinB/b, where A is an angle and a is a length of a triangle
this may help: https://www.youtube.com/watch?v=RL2F49BwQTA

~
Thank you so much,
you have literally saved me
because I doing an exam practice paper for my maths revision
and I was panicking
I wouldn't call it revision though as Im asking for help
well that's just me LOL
thanks again
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Virolite
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#6
Report 6 years ago
#6
(Original post by AmirahxRashid)
Thank you so much,
you have literally saved me
because I doing an exam practice paper for my maths revision
and I was panicking
I wouldn't call it revision though as Im asking for help
well that's just me LOL
thanks again
no worries pal
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34908seikj
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#7
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#7
Sine rule for angles is Sin(A)/a=Sin(B)/b
Cosine rule for angles is Cos(A) =b2 + c2 - a2/2bc Therefore A = Cos-1(b2 + c2 - a2/2bc)
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AmirahxRashid
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#8
Report Thread starter 6 years ago
#8
(Original post by 34908seikj)
Sine rule for angles is Sin(A)/a=Sin(B)/b
Cosine rule for angles is Cos(A) =b2 + c2 - a2/2bc Therefore A = Cos-1(b2 + c2 - a2/2bc)
Thank you so much
im guessing u just rearranged the formula right
thanks
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