Everyone please correct, suggest and add. Rep is appreciated,
What i got so far.
1) isotope - same no. protons, diff no. neutrons
92*1.6*10^-19/mass no. * 1.67*10^-something I got 3.7 * 10^something 3 electrons removed to 89 fill in -
mass number stays the same, 93 protons, (0, -1 )for beta minus particle and antineutrino
Pair production
Rest Energies of electron and positron must be equal or greater to photon in order to conserve energy. Below energy pair production will not take place
Show that, using (0.51MeV x 2) in data sheet. = 1.02MeV
Photon frequency ( 1.6X10^13/h) = 2.4x10^20 Hz
lepton number conserved (0=0)Kaon decays via weak, so pi 0
Diodes - 6 marker is June 2009, refer to MS
Switch wiring to cell so that opposite flow, Or Switch diode so reverse bias.
Resistance increases, Voltage Decreases. ( i put it so that Res decreases which is wrong as its non-ohmic)
Heating Element BS
V peak to Peak is 650V
4040W, 228V,
7) Current not flowing, therefore dot on the oscilloscope
PQ is Emf=6Volts
current=0.28A,(5/18) I used 5 as it was in parallel with the internal res so voltage has to be 5?.
Internal resistance = 3.6 Ohms. / 3.8 Due to rounding( Using Emf - V = 1)
Prediction - 56/55 For an A