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    hey.
    Its been a while since i have done C3 could somone jog my memory on how i am meant to do 8(ii).
    Any help would be great, thanks.
    https://7c95ed1f832973eac0c6e1a52b08...20C3%20OCR.pdf
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    (Original post by SamuelN98)
    hey.
    Its been a while since i have done C3 could somone jog my memory on how i am meant to do 8(ii).
    Any help would be great, thanks.
    https://7c95ed1f832973eac0c6e1a52b08...20C3%20OCR.pdf
    g(3) = 4(3) - 2a = 12-2a.

    f(g(3)) = f(12-2a) = (12-2a)^2 + 4a(12-2a) + a^2 = 69. Solve.
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    (Original post by SamuelN98)
    hey.
    Its been a while since i have done C3 could somone jog my memory on how i am meant to do 8(ii).
    Any help would be great, thanks.
    https://7c95ed1f832973eac0c6e1a52b08...20C3%20OCR.pdf
    fg(x) means that you find g(x) then put that output into f(x). You can read it as f(g(x)).
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    (Original post by Zacken)
    g(3) = 4(3) - 2a = 12-2a.

    f(g(3)) = f(12-2a) = (12-2a)^2 + 4a(12-2a) + a^2 = 69. Solve.
    (Original post by SeanFM)
    fg(x) means that you find g(x) then put that output into f(x). You can read it as f(g(x)).
    Thank you for the help.
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    (Original post by SamuelN98)
    Thank you for the help.
    No problem.
 
 
 
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