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# C1 question Watch

1. https://917c8db4f385e20466384eff57d8...%20Edexcel.pdf

How do you do question 6d? June 2013 R paper

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2. You do 50 times a2 plus 50 times 1 the answer should be 25
3. (Original post by jenqo)
https://917c8db4f385e20466384eff57d8...%20Edexcel.pdf

How do you do question 6d? June 2013 R paper


Wait I don't think you can do the above way because the sequence doesn't have a common difference as such, or rather it just switches between two values.

You should know from parts a b c that U1 = 1, U2 = 1-K (you'll have a number but I couldn't be bothered working it out) and U3 = 1. We have already seen that if you put 1 into the recurrence relation formula you get out 1-K so U4 must be 1-K and this in turn means U5 = 1... This means that all the 50 even terms are 1 and the 50 odd terms are all 1-K. Therefore to find the total you'd add 50 + 50(1-K)
Spoiler:
Show
Btw was K 3/2? Didn't work it out I just think I remember it being that... Also I think I remember the answer being 25?
4. (Original post by jenqo)
https://917c8db4f385e20466384eff57d8...%20Edexcel.pdf

How do you do question 6d? June 2013 R paper


Here you go
Attached Images

5. (Original post by #sarahsmith2)
Wait I don't think you can do the above way because the sequence doesn't have a common difference as such, or rather it just switches between two values.

You should know from parts a b c that U1 = 1, U2 = 1-K (you'll have a number but I couldn't be bothered working it out) and U3 = 1. We have already seen that if you put 1 into the recurrence relation formula you get out 1-K so U4 must be 1-K and this in turn means U5 = 1... This means that all the 50 even terms are 1 and the 50 odd terms are all 1-K. Therefore to find the total you'd add 50 + 50(1-K)
Spoiler:
Show
Btw was K 3/2? Didn't work it out I just think I remember it being that... Also I think I remember the answer being 25?
Thank you very much
6. (Original post by JohnJ100)
Here you go
Bless you, I really appreciate it

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