Cambridge Chat (previously New Cambridge Students Entry 2004)

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Camford
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#4421
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#4421
ages are 2, 2, 9
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Willa
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#4422
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#4422
how does that make use of the second clue?
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Camford
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#4423
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#4423
(Original post by Camford)
ages are 2, 2, 9
Alright I cheated bit, ok? I'm a cheater by nature. I started cheating since the age of 8. Now I am very experienced cheater, I think I probably cheated my way through the Dec interview into Cambridge.
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Willa
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#4424
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#4424
oh my god I see the answer now

You have to use ALL 3...that's the point....you cant just use the first 2.....OH MY GOD THATS SO ANNOYING!
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Camford
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#4425
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#4425
See the full reasoning here.
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Camford
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#4426
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#4426
*Camford once again kneels in front of St. Google.*
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Squishy
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#4427
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#4427
*sigh* Cheat.
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Fluffstar
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#4428
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#4428
(Original post by Squishy)
*sigh* Cheat.
whats worse, cheating or not even bothering?
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Squishy
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#4429
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#4429
wibble

[UK, perh. originally from the first "Roger Irrelevant"
strip in "VIZ" comics] 1. n.,v. Commonly used to describe chatter,
content-free remarks or other essentially meaningless contributions
to threads in newsgroups. "Oh, rspence is wibbling again". 2. [UK
IRC] An explicit on-line no-op equivalent to humma. 3. One of the
preferred metasyntactic variables in the UK, forming a series with
'wobble', 'wubble', and 'flob' (attributed to the hilarious
historical comedy "Blackadder"). 4. A pronounciation of the letters
"www", as seen in URLs; i.e., www.foo.com may be pronounced
"wibble dot foo dot com" (compare dub dub dub).
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Squishy
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#4430
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#4430
(Original post by Fluffstar)
whats worse, cheating or not even bothering?
Other people bothered without cheating.
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Camford
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#4431
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#4431
(Original post by Squishy)
Other people bothered without cheating.
I know. I could have done better at school if I didn't think about cheating all that much... *Camford is ashamed of himself.*
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Squishy
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#4432
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#4432
(Original post by Camford)
I know. I could have done better at school if I didn't think about cheating all that much... *Camford is ashamed of himself.*
Hehe, I wasn't having a go at you. I just always like to solve stuff myself...my physics teacher actually used the problem to allow us to work out his house number so that we could go to a dinner he was hosting. I suppose I could've just looked him up in the phone directory, but it would've taken the fun out of it.
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Camford
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#4433
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#4433
Squishy, fancy another maths Q?
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Camford
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#4434
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#4434
Bah! I'm posting the question here anyway.

Find an general equation, or groups of equations which describe numbers which are triangle numbers as well as square number. If you it's the latter, please states starting values.
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fishpaste
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#4435
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#4435
I got to saying that such numbers are when

8p^2 + 1 is an odd square. if you can generate such p, the p(p+1)/2 will be a triangular square, but I can't generate 8p^2 + 1 which are odd squares


*edit* just seen that 8p^2 + 1 is always odd because 8p^2 is clearly odd so +1 makes it odd. so the "odd" part is redundant

so basically if you could solve

8p^2 + 1 = q^2

you could generate triangular squares. like consider p = 1, the expression is consistent for integers (with q = 3), then p(p+1)/2 = 1 which is a triangular number

or p = 6 ... (makes q = 17)

p(p+1)/2 = 6*7/2 = 21 ...which is another triangular number
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Squishy
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#4436
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#4436
Shouldn't we take this elsewhere before this thread is moved to the Maths forum?
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Camford
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#4437
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#4437
(Original post by Squishy)
Shouldn't we take this elsewhere before this thread is moved to the Maths forum?
If you get some mathematicain to analyse this thread, it has got less than 50% of mathematical contents in it. Therefore, this thread can not be dubbed as a mathematics thread in principle. Which means we are safe. Beside, we are all going to Cambridge next year.
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Willa
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#4438
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#4438
i'm stuck on the same stage fishpaste
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Squishy
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#4439
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#4439
LOL, we could argue it on a technicality.

But I just think we're really excluding the people here who don't like maths (which is most of them).

BTW Camford, are you doing Physics for your NatSci option next year?
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Camford
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#4440
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#4440
(Original post by fishpaste)
I got to saying that such numbers are when

8p^2 + 1 is an odd square. if you can generate such p, the p(p+1)/2 will be a triangular square, but I can't generate 8p^2 + 1 which are odd squares
A friend (going Christ but don't use UKL) and I spent about 40 mins on this problem during a maths lesson 3 months ago. We managed to get two sequences of numbers which generate numbers that fit the criteria of the quetions when put into a equation. But, unfortunately, I lost the sheet of paper to my beloved bin bag after the lesson. So, now, I'm just as clueless as you are, mate.
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