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    (Original post by crana9)
    no, it applies to the ketters in any form, spoken, handwritten, typed, sprayed in 6 foot letters on my ceiling...

    ok, net question, how do i sketch a graph of Y = ae^(t ln b) ? of Y against t?
    just be methodical.

    YOu know that Y > 0 for any t

    you know that when t is very large, Y is off at positive infinity

    when t goes off to minus infinity y goes to 0 but doesn't actually hit it.

    you know that when t = 0, then Y = A

    then just join it all up into a nice smooth exponential looking curve
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    (Original post by Camford)
    If you want a straight line, you don't plot y against t. You plot LnY against t.
    indeed, and alot of the time they will want the straight lines.
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    (Original post by Camford)
    If you want a straight line, you don't plot y against t. You plot LnY against t.

    well, i dont want a damn straight line. you cant say "oh i didnt fell like sketching the one you asked me to, i thought id do a completely differnet one insyead " now can you
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    AHAHAHA i said it was exponential before you told me

    GO ME
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    (Original post by crana9)
    AHAHAHA i said it was exponential before you told me

    GO ME
    Get Maple and the Machine do all the dirty work for you.
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    (Original post by Camford)
    Get Maple and the Machine do all the dirty work for you.
    will they be there in my exam though? no? thought not
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    (Original post by fishpaste)
    just be methodical.

    YOu know that Y > 0 for any t

    you know that when t is very large, Y is off at positive infinity

    when t goes off to minus infinity y goes to 0 but doesn't actually hit it.

    you know that when t = 0, then Y = A

    then just join it all up into a nice smooth exponential looking curve
    Isn't the thing just y = a(b^t)?
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    (Original post by crana9)
    will they be there in my exam though? no? thought not
    That's what the machines are made for, do human's dirty work. That's so unreasonable.
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    I'm off to gardies at about 9:30. All these maths thought burns up calaries real fast.
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    (Original post by Camford)
    Isn't the thing just y = a(b^t)?

    yes but there's the whole thing about "what is the definition of b^t?" and they get quite fussy on it since clearly you or I do not know what 7^3.8 is really.
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    (Original post by fishpaste)
    yes but there's the whole thing about "what is the definition of b^t?" and they get quite fussy on it since clearly you or I do not know what 7^3.8 is really.
    em... 5th root of 7^19.
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    (Original post by Camford)
    I am currently in the computer room because I need this thing called ML to do my calculations for me. Wonderful stuff. Anyway, if I am in my room, then I'll be very happy to answer anything I can answer.
    Moscow ML is available for downloading onto your own computers (well Cambridge ML is too, but its hard to find and rubbish). PolyML isn't too bad, arbitrary sized integers et al.
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    (Original post by Alaric)
    Moscow ML is available for downloading onto your own computers (well Cambridge ML is too, but its hard to find and rubbish). PolyML isn't too bad, arbitrary sized integers et al.
    I am the only CompSci in the whole world without a comp in his own room!! I must suffer the consequences.
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    (Original post by fishpaste)
    yes but there's the whole thing about "what is the definition of b^t?" and they get quite fussy on it since clearly you or I do not know what 7^3.8 is really.
    ML says 7^3.8 is 1626.94380307
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    (Original post by Camford)
    em... 5th root of 7^19.
    but it's just better to say e^(3.8 * ln7) =P better defined!
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    (Original post by Camford)
    I am the only CompSci in the whole world without a comp in his own room!! I must suffer the consequences.
    Fair enough!
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    (Original post by fishpaste)
    but it's just better to say e^(3.8 * ln7) =P better defined!
    so what e^3.8 then?
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    (Original post by Camford)
    so what e^3.8 then?
    1 + x/1! + x^2/2! + x^3/3! + ... + x^n/n!


    where x = 3.8
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    (Original post by fishpaste)
    but it's just better to say e^(3.8 * ln7) =P better defined!
    I'm not going to argue with you over definition. Can't beat a mathsmo in his back yard.
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    (Original post by fishpaste)
    1 + x/1! + x^2/2! + x^3/3! + ... + x^n/n!


    where x = 3.8
    You win......
 
 
 
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