Cambridge Chat (previously New Cambridge Students Entry 2004)

Int by parts. That trick works well on these bitches.

Reply 11321

yes i do but i get a 0.5 which the answers says isnt ther!

Reply 11322

http://scholar.google.com/scholar?hl=en&lr=&safe=off&q=cosh-1x

3 results on cosh-1x

those fail to help

I know that. But it's google Scholar Beta.... :biggrin:

Reply 11325

Katie J

10

I'm having a food crisis! I'm hungry and don't have anything other than pasta which I have eaten for the past few days (rowing :rolleyes:

) and supernoodles, rice, tuna, tomato sauce and other useless stuff like herbs and salt. I've run out of porridge and only have some green bananas! I really should have gone shopping today instead of writing my essays!
Where can I get food this time of night on a Sunday??

Reply 11326

May I suggest Gardie's to you?

Reply 11327

fishpaste

Willa

ok so lets try again, see if the answer suddenly comes to me...someone answer it non the less

integrate cosh-1 x........i get a 0.5 appearing, someone help!

if it's not in the answer it's probably been absorbed into the constant. but i'm not 100% as to where you're saying it's appearing

Reply 11328

Katie J

10

Camford

May I suggest Gardie's to you?

Ergh, I can't stomach that now! I would go out for a meal but too much work to do, might have to cycle down to the co-op, I'm very hungry!!

Reply 11329

I have enough chocolate to feed a small nation in my room. Fancy some?

Reply 11330

crana9

2

eat the supernoodles tonight, have rice and tina salad with tomato sauce tomorro for lunc / dinner, try and go shopin tomorrow.

Reply 11331

i gave up on that question, i'm now on trying to express tanh-1 as a logarithm! any help?

Reply 11332

Willa

i gave up on that question, i'm now on trying to express tanh-1 as a logarithm! any help?

what's tanhx in exponential? (e^x-e^-x)/(e^x+e^-x) = tanhx. solve for x as if you are dealing with an quadratic eqtn in e^x.

Reply 11333

how can you multiply something like that into a quadratic exactly...i'm being v slow tonight

Reply 11334

let that thingumy = y. multiply top and bottom by e^x. and solve for e^2x.

Reply 11335

I'm procrastinating... I don't want to do read my physics lab handbook. Will, we get to play that thingumy tomorrow, don't we? Last practical of this term. Yipee!! But I am slightly depressed with the thoughts of going home... without anyone to talk to... without internet...

Reply 11336

http://www.goyk.com/flash.asp?path=265

Reply 11337

but then you have (e^2y - 1)/(e^2y+1)....where do you go from there to get a nice quadratic of e^x?

Reply 11338

where's the y from?

(e^x - e^-x)/(e^x + e^-x) = y
(e^2x - 1)/(e^2x+1)=y
e^2x - 1=ye^2x +y

Reply 11339