I was doing Q4 on this paper and i came across a hardy weinberg question:
Polydactyly in cats is an inherited condition in which cats have extra toes. The allele for
polydactyly is dominant.
In a population, 19% of cats had extra toes. Use the Hardy-Weinberg equation to
calculate the frequency of the recessive allele for this gene in this population.
The answer is supposed to be 0.9.Somebody please help??
Unit 4 Biology June 15 watch
- Thread Starter
- 18-05-2016 19:55
- 11-06-2016 13:11
The allele for polydactyly is dominant so this is p2 and 2pq which means you have to find q2. Turn 19% into a frequency - 19/100= 0.19 which is p2+2pq. As you want to find q2 do 1-0.19= 0.81 but now you want to find the allele which is q instead of the genotype so do the square root of 0.81 which is 0.9... Hope this helps, I'm not great at explaining!
- 11-06-2016 14:56
1-0.19 = 0.81= q^2 (recessive)
Square root 0.81 to get q = 0.9
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