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    does anyone have a solution to qu 1 on the c3 june 2014 paper..
    can't seem to get my head around it at the minute!!
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    The Simpson's Rule Question? This was actually a fairly straight forward Simpson's Rule question as you didn't need to calculate h as it's already given to you (3 metres).

    Yo (first value) is 30m and Yn (last value) is also 30m
    Y1 is 28, Y3 is 19, Y5 is 18.5, Y7 is 21 - these are your "odd y values"
    Y2 is 22, Y4 is 16, Y6 is 20.8 - these are your "even y values"

    The Simpson's Rule equation is given to you in the exams, and is h/3[(Yo+Yn)+4(Y1+Y3+Y5+Y7)+2(Y2+Y4+Y 6)]. I always remember it as h/3[(first+last)+4(sum of "odd y values" )+2(sum of "even y values" )]

    Your equation will be 3/3[(30+30)+4(28+19+18.5+21)+2(22+16 +20.8)] = 523.6 = 524m^2 (Answer)

    Hopefully this helps! I'm rubbish at explaining Maths. Dreading tomorrow's exam.
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    How did people find it?
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    (Original post by Foutre en L'air)
    How did people find it?
    Hardest c3 exam ever by far.
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    (Original post by Golden hawk)
    Hardest c3 exam ever by far.
    Really? I think the only mistake I made was mistaking a century to be 10 years , but I've known the C3 content for almost a year!

    Where did you find hardest?
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    (Original post by Foutre en L'air)
    Really? I think the only mistake I made was mistaking a century to be 10 years , but I've known the C3 content for almost a year!

    Where did you find hardest?
    The half life and proving the positive values of x
 
 
 
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