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    Name:  image.jpg
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Size:  501.9 KBHey guys,

    For c) to find R, I simply added the vector for the original position vector to the vector of constant velocity*300 (since 1500-1200=300). But according to the mark scheme I should *3?

    Why?

    The units for t are not given, and it sounds strange to use 1200 hours, but I can't see where 3 is coming from!

    Thanks
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    (Original post by Serine)
    Name:  image.jpg
Views: 45
Size:  501.9 KBHey guys,

    For c) to find R, I simply added the vector for the original position vector to the vector of constant velocity*300 (since 1500-1200=300). But according to the mark scheme I should *3?

    Why?

    The units for t are not given, and it sounds strange to use 1200 hours, but I can't see where 3 is coming from!

    Thanks
    The velocity is in kilometres per hour.

    Have you heard of military time?

    1200 is noon

    1300 is one o'clock

    1400 is two o'clock

    1500 is 3 o'clock

    So since you have three hours between 1200 and 1500, and your velocity is in kilometres per hour, you multiply that by 3.
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    :banghead::banghead: Thanks for the clarification! What a silly mistake 🙈
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    (Original post by Serine)
    :banghead::banghead: Thanks for the clarification! What a silly mistake 🙈
    No worries. :-)
 
 
 
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