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    This is from the lecture, can someone explain why there's a square beside the T in the first line? I understand what's been written in the explanation but still don't know where the square comes from.Name:  20160521_130929.jpg
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    Im not sure what you mean. Im guessing you mean this?
    \displaystyle \left[\frac{L}{T^2}\right] = [L]^m [T]^{-2m}
    If that is the case then its because you have expanded the power out.
    \displaystyle \left[\frac{a}{b}\right]^c \rightarrow [a]^c \times [b]^{-c}
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    (Original post by Airess3)
    This is from the lecture, can someone explain why there's a square beside the T in the first line? I understand what's been written in the explanation but still don't know where the square comes from.Name:  20160521_130929.jpg
Views: 67
Size:  509.7 KB

    If you look at your lecture note, there is an equation which say

    s = k am tn

    The dimension for [a] is [L/T2] .
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    (Original post by Airess3)
    This is from the lecture, can someone explain why there's a square beside the T in the first line? I understand what's been written in the explanation but still don't know where the square comes from.Name:  20160521_130929.jpg
Views: 67
Size:  509.7 KB
    What square? It simply says the units for acceleration are length/time_squared. Since the equation is a^m, the units are also raised ^m which gives length^m multiplied by (T^-2)^m . Square brackets are put around length and time to show we are equating units instead of variables.
 
 
 
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