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    HI
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    I get that it is a stretch in x direction but i don't understand how you work out the scale factor?
    Any help?
    Many thanks
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    (Original post by pygmypossum)
    HI
    Name:  Capture.PNG
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    I get that it is a stretch in x direction but i don't understand how you work out the scale factor?
    Any help?
    Many thanks
    If you call the first one f(x) then you should spot the second one is f(2x). Can you see why this is true?

    The transformation f(ax) is a stretch scale factor \frac{1}{a} parallel to the x-axis.
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    (Original post by Zacken)
    If you call the first one f(x) then you should spot the second one is f(2x). Can you see why this is true?

    The transformation f(ax) is a stretch scale factor \frac{1}{a} parallel to the x-axis.
    No sorry I don't understand how its (2x)??
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    (Original post by pygmypossum)
    No sorry I don't understand how its (2x)??
    If you have f(x) = \sqrt{x^3 + 1} then if you replace all the x's with 2x you get f(2x) = \sqrt{(2x)^3 +1} = \sqrt{8x^3 + 1}, which is precisely the second function you have.
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    (Original post by Zacken)
    If you have f(x) = \sqrt{x^3 + 1} then if you replace all the x's with 2x you get f(2x) = \sqrt{(2x)^3 +1} = \sqrt{8x^3 + 1}, which is precisely the second function you have.
    Ah that makes sense! So is the answer 1/2?
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    (Original post by pygmypossum)
    Ah that makes sense! So is the answer 1/2?
    Yeah.
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    (Original post by Zacken)
    Yeah.
    Thank you!
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    (Original post by pygmypossum)
    Thank you!
    No problem. :-)
 
 
 
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