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# Physics Electric fields Watch

Page 11 5bi why use v as 300?
2. This is because the question states that the charge is midway between the parralel plates. This means that from the ion and the bottom plate the potential difference it 300V (Half of 600V). So the ion is being moves through a potential of 300V and not 600V.
3. (Original post by SirRaza97)
This is because the question states that the charge is midway between the parralel plates. This means that from the ion and the bottom plate the potential difference it 300V (Half of 600V). So the ion is being moves through a potential of 300V and not 600V.
is this the same for a beam of electrons that enter e field midway?
4. (Original post by jonnypdot)
is this the same for a beam of electrons that enter e field midway?
I believe so.
5. (Original post by SirRaza97)
I believe so.
1. can i you also clear this up for me,
we have 2 positive charges which are not equal, and are separated by distance d, the electric field strength at the mid point of their separation will be just the sum of their electric fields at a distance d/2?

If charges were now both negative i would have to take into account direction of the E fields, if they were unlike charges will i also add the E fields?

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