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# Potential Divider Definition, AQA Physics watch

1. What is the definition of potential divider according to the mark scheme of AQA?
2. I don think there is a definition to learn. Just understanding how they work so you can apply it to calculations. I could be wrong though
3. I thought it was two or more resistors connected to a source of fixed pd?
4. I found the question but I don't know where its from. all i know that its from the new spec

5. The mark scheme answer is: A combination of resistors in series connected across avoltage source.
6. A potential divider is a simple circuit that uses resistors/thermistors/LDRs to supply a variable potential difference.
At its simplest, a potential divider is a circuit with a voltage source and resistors in series. The potential of the voltage source (e.g. power supply) is divided in the ratio of the resistances.

This means that if you had a 2 ohm resistor and a 3 ohm resistor, there would be 2/5 of the p.d. across the 2 ohm resistor and 3/5 of p.d. across the 3 ohms. Therefore resistances can be chosen to get a required voltage across one of the resistors.

This pretty much explains it fully in different ways, but it's all correct!
7. (Original post by Starlotte)
A potential divider is a simple circuit that uses resistors/thermistors/LDRs to supply a variable potential difference.
At its simplest, a potential divider is a circuit with a voltage source and resistors in series. The potential of the voltage source (e.g. power supply) is divided in the ratio of the resistances.

This means that if you had a 2 ohm resistor and a 3 ohm resistor, there would be 2/5 of the p.d. across the 2 ohm resistor and 3/5 of p.d. across the 3 ohms. Therefore resistances can be chosen to get a required voltage across one of the resistors.

This pretty much explains it fully in different ways, but it's all correct!
I understand it better now, thank you very much
8. (Original post by Megannk)
The mark scheme answer is: A combination of resistors in series connected across avoltage source.
Thanks man, I appreciate the help

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