Year 12s: are you considering an apprenticeship or degree apprenticeship?

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Year 12s: are you considering an apprenticeship or degree apprenticeship?

Changes to Profiles on TSR

Integration of (1/kx)

If you want to do this:

\int{\frac{1}{kx}}

where k is a constant, you can either take that as:

\int{\frac{1}{k}*\frac{1}{x}}

or

\int{\frac{1}{kx}}

, which respectively integrate to

\frac{1}{k}lnx

and

\frac{1}{k}lnkx

. But obviously they're different so what is the explanation???????

You are forgetting the constant that comes out as well (the + C) which can combine with whatever is inside the ln

mrsmann

If you want to do this:

\int{\frac{1}{kx}}

where k is a constant, you can either take that as:

\int{\frac{1}{k}*\frac{1}{x}}

or

\int{\frac{1}{kx}}

, which respectively integrate to

\frac{1}{k}lnx

and

\frac{1}{k}lnkx

. But obviously they're different so what is the explanation???????

\frac{1}{k}lnkx=\frac{1}{k}\ln{k}+\frac{\ln{x}}{k}=\frac{\ln{x}}{k}+c

OP

Ok thanks for the replies.

+c sucks

mrsmann

Ok thanks for the replies.

+c sucks

+c > you.

OP

generalebriety

mrsmann > +c > me.

Fixed!

mrsmann

Fixed!

Ah yes. I forgot to carry the 1.

OP

I don't get it :frown:

:frown:

1/k lnk is just a constant....

Original post by Sudarshan stud

U can also do like this right take (kx) to numerator it will become (kx)pow -1, then integrate, it becomes k×((x)pow-2/-2)..... Then which is right.........????????

This thread is 12 years old. When you integrate you add 1 to the power. You have subtracted 1, but it doesn't work when the power is - 1. I suggest you make a new thread instead.

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