I have been asked:
"how much lead (IV) oxide would be required to make up 150 grams of sodium oxide?
The equation is PbO2+2Na2SO4--> 1 Pb(SO4)2 +2 Na2O
And I am lost.
First off, I worked out the number of moles for the sodium oxide which I found to be:
150 g (mass) / 62g (gfm) =2.42 moles.
I want mass of PbO2; ergo M = N x gfm
So I figured 239.2 (gfm of
But eh that's entirely wrong
Where HAVE I went wrong......?
The Answer SHOULD be: 289 grams :\
Or does it play no part?