chloe.oakes
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I've factorised x^-2 - 16 = 0
to (1/x -4) (1/x + 4) what are the two values of x? I know if it was (2x -3) x= 3/2
Thanks ))
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Zacken
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(Original post by chloe.oakes)
I've factorised x^-2 - 16 = 0
to (1/x -4) (1/x + 4) what are the two values of x? I know if it was (2x -3) x= 3/2
Thanks ))
So it's the same thing here, isn't it? either \frac{1}{x} - 4 = 0 or \frac{1}{x} + 4 = 0.
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