If Kc is a numerical value to describe the position of eq'm, how can we say that Kc does not change when pressure changes?
e.g. for the reaction 2X + 2Y --> Z
Increasing pressure shifts eq'm to the right - the side of fewer gas moles. How is Kc unaffected by this is Kc describes the position of eq'm????
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Kc vs position of equilibrium watch
- Thread Starter
- 24-05-2016 21:01
- Official Rep
- 26-05-2016 22:20
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Just quoting in Puddles the Monkey so she can move the thread if needed
Spoiler:Show(Original post by Puddles the Monkey)