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#1
Hey guys
In C2 for logarithms how do you manipulate a question with three minus logs??
Coz I know that when there's a minus you divide the logs but how do you do that if there are three minuses??
Ex: log(2)11x+3 - log(2)5x - 2log(2)x = 1

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2 years ago
#2
(Original post by CrystalPark)
Hey guys
In C2 for logarithms how do you manipulate a question with three minus logs??
Coz I know that when there's a minus you divide the logs but how do you do that if there are three minuses??
Ex: log(2)11x+3 - log(2)5x - 2log(2)x = 1

log(x)-log(y)=log(x/y)
log(x/y) - logz = log(x/yz)

Take it step by step remember you cannot do the following 2log(x) - log(y) = 2log(x/y) noooo
2log(x) -log(y) = Log(x^2/y)
0
2 years ago
#3
.
0
#4
(Original post by jonnypdot)
log(x)-log(y)=log(x/y)
log(x/y) - logz = log(x/yz)

Take it step by step remember you cannot do the following 2log(x) - log(y) = 2log(x/y) noooo
2log(x) -log(y) = Log(x^2/y)
Thank you so much!!!! 👌🏻💯
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