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    Looking for 2017 unofficial mark scheme?

    It's here!

    PDF COPY: http://docdro.id/9ari5uF
    PDF DIRECT DL: https://www.docdroid.net/file/downlo...k-schemev5.pdf

    USE LINKED MARKSCHEME NOT ATTACHED ONE, THIS ONE IS UPDATED.

    1 Geometric series question, prove a=64 given S_4=175 and r=\frac{3}{4} then workout sum to infinity. Then find the difference between the 9th and 10th term

    2 Trapezium rule. y=8-2^{x-1} in the interval [0,4] with 4 trapeziums

    3 Circle centred at (7,8). Find the equation of it and of a tangent at point (10,13)

    4 where f x =6x^3+13x^2-4 find the remainder when divided by (2x+3) then factorise it fully given (x+2) is a factor.

    5 Expansion of (2-9x)^4. The using that expand (1+kx)(2-9x)^4 in the form A -232x + Bx^2 given the coefficient of x

    6 1-2\cos(\theta - \frac{\pi}{5})=0 solve for \theta and 4\cos^2 x + 7\sin x - 2 = 0

    7 This was \int (3x-x^{\frac{3}{2}}) dx and then find the limits (where it crossed the x axis.

    8 \log_3(3b+1)-\log_3(3a-2)=-1, write b in terms of a then find x given 2^{2x+5}-7(2^x)=0.

    9 Find optimum perimeter of a funny shape which comprised a rectangle, sector and a equilateral triangle, need diagram.
    Image by Cake_Chan
    Equations given, that needed proving are, y=\frac{500}{x}-\frac{x}{24}(4\pi+3\sqrt{3})
    and P=\frac{1000}{x}+\frac{x}{24}(4\  pi+36-3\sqrt{3})


    My answers:
    1 a) (2 marks) proof
    b) (2 marks) 256
    c) (2 marks) 1.602

    2 a) (1 mark) 7
    b) (3 marks) 20.75
    c) (2 marks) 5.75

    3 a) (2 marks) \sqrt{34}
    b) (3 marks) (x-7)^2+(y-8)^2=34
    c) (4 marks) 3x+5y-95=0

    4 a) (2 marks) 5
    b) (2 marks) f(-2)=0
    c) (4 marks) f(x)=(x+2)(3x+2)(2x-1)

    5 a) (4 marks) 16-288x+1944x^2
    b) (1 mark) 16
    c) (2 marks) \frac{7}{2}
    d) (2 marks) 936

    6 i) (3 marks) \frac{8\pi}{15}or \frac{-2\pi}{15}
    ii) (6 marks) 345.5$^{\circ}$ or 194.5$^{\circ}$

    7 a) (3 marks) \frac{3}{2}x^2-\frac{2}{5}x^{\frac{5}{2}}+c
    b) (3 marks) 24.3

    8 i) (3 marks) b= \frac{3a-5}{9}
    ii) (4 marks) -2.19

    9 a) (2 marks) \frac{\pi x^2}{3}
    b) (3 marks) proof
    c) (3 marks) proof
    d) (5 marks) x=16.63 P= 120m
    e) (2 marks)  f''x = 0.437 > 0 \therefore is a minimum at x

    This is useful and was spread out over another thread so I thought I would post it here. The missed answers were all either proofs or not suited to a single number response.

    EDIT: 9c is P=\frac{1000}{x}+\frac{x}{24}(4\  pi+36-3\sqrt{3}) not P=\frac{1000}{x}+\frac{x}{24}(4\  pi+36-3\sqrt{4})
    8ii is 2^{2x+5}-7(2^x)=0 not 2^{2x+5}-7(2^x)=-1
    6a is 1-2\cos(\theta - \frac{\pi}{5})=0 not 1-2\sin(\theta - \frac{\pi}{5})=0 thanks for spotting this one UKoE Luna


    FINAL MARK SCHEME UPLOADED C3 next

    http://www.thestudentroom.co.uk/show....php?t=4117259 <- AstarAstarA did a very good one here, better break down of the marks.
    Attached Images
  1. File Type: pdf unofficial-mark-scheme.pdf (110.7 KB, 7509 views)
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    Thanks!
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    TeeEm
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    (Original post by edothero)
    TeeEm
    yes
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    1.b. Is wrong. The answer is -1.602. It has to be negative because in geometric sequence, the biggest term is subtract by the smallest.

    Therefore 64(3/4)^9 - 64(3/4)^8 = -1.602 (to three decimal places).

    P.S. I don't know if the markscheme would say 'ignore' signs.
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    (Original post by Qweudhs56)
    1.b. Is wrong. The answer is -1.602. It has to be negative because in geometric sequence, the biggest term is subtract by the smallest.

    Therefore 64(3/4)^9 - 64(3/4)^8 = -1.602 (to three decimal places).

    P.S. I don't know if the markscheme would say 'ignore' signs.
    It asked for the difference I think it would say ignore signs
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    (Original post by X_IDE_sidf)
    It asked for the difference I think it would say ignore signs
    If it asked for difference, I am pretty sure it would be a negative sign. Since when the lower term is minus by the bigger term in order to calculate the difference?
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    how many marks was 1a?
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    How many makes would I loose for not putting it in radians. It didn't ask for radians
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    (Original post by Qweudhs56)
    If it asked for difference, I am pretty sure it would be a negative sign. Since when the lower term is minus by the bigger term in order to calculate the difference?
    Difference is absolute. It is asking for how different the numbers are. |u_9-u_{10}| = |u_{10}-u_9| The positive is more correct.
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    Whats 8i)?????
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    (Original post by Verdahf)
    Whats 8i)?????
    Thankyou, sorry I missed that, \log_3(3b+1)-\log_3(a-2)=-1, write b in terms of a
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    forgot to encode my answer to 6i how many marks would i lose?
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    (Original post by Verdahf)
    Whats 8i)?????
    the answer was b= (3a+5)/9
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    (Original post by X_IDE_sidf)
    Thankyou, sorry I missed that, \log_3(3b+1)-\log_3(a-2)=-1, write b in terms of a
    Do you know how many marks this part was for?
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    (Original post by dididid)
    the answer was b= (3a+5)/9
    Do you remember the number of marks this was worth, I think it was 3.
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    YESSSSS
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    (Original post by X_IDE_sidf)
    Do you remember the number of marks this was worth, I think it was 3.
    yh i think 3 is right
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    what are your grade boundary predictions?
    i got between 70-73 marks how many ums would that be about?
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    for the first part of the logs

    I said 1/3 = 3b+1/a-2

    then 1/3a -2/3= 3b+1

    1/3a-5/3=3b

    1/3a-5/3 all divided by 3 = b

    Is this correct and how many marks would i lose if incorrect?
 
 
 
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