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#1
Attachment 538139538141

Hi for this question (photos), part D where you have to find when it is past 15km again

Im confused to why the equation for distance is being squared? Why are we squaring the equation am I missing some concept?
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2 years ago
#2
(Original post by eyeman567)
Attachment 538139538141

Hi for this question (photos), part D where you have to find when it is past 15km again

Im confused to why the equation for distance is being squared? Why are we squaring the equation am I missing some concept?
I am not sure what you mean by squaring the equation, you are simply substituting d = 15 into the equation from the previous part?
0
2 years ago
#3
If you are referring to why we square both sides of the equation in part C, this is simply to remove the ugly square root that we get from finding the magnitude of the PQ vector!
1
#4
(Original post by Mav1)
If you are referring to why we square both sides of the equation in part C, this is simply to remove the ugly square root that we get from finding the magnitude of the PQ vector!
Ah, I see, I realize that by the 15 being squared it is the same as the equation normally. Thank you!
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