# Mr M's OCR (not OCR MEI) Core 2 Answers May 2016Watch

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#1
Mr M's OCR (not OCR MEI) Core 2 Answers May 2016

1. (i) 10 cm (2 marks)

(ii) 5.04 cm (2 marks)

2. (i) (2 marks)

(ii) (3 marks)

3. (i) (4 marks)

(ii) (2 marks)

4. (i) (2 marks)

(ii) (4 marks)

5. (a) (3 marks)

(b) (i) (4 marks)

(ii) 4 (1 mark)

6. (i) (3 marks)

(ii) (2 marks)

(iii) (6 marks)

7. (i) Quotient and remainder 0 (3 marks)

(ii) or or (3 marks)

(iii) Show (2 marks)

(iv) (4 marks)

8. (i) Translation by 2 units in the positive x direction (2 marks)

(ii) Stretch parallel to the y axis scale factor (2 marks)

(iii) Sketch showing as the only point of intersection (2 marks)

(iv) (3 marks)

(v) 9.60 (3 marks)

9. (i) (1 mark)

(ii) and (3 marks)

(iii) and (4 marks)

Sorry guys I made a mess of 9(ii) at the start - I didn't notice k had to be positive. It's right now.
4
2 years ago
#2
for 4ii) why was x=-3 not a valid answer?
0
2 years ago
#3
(Original post by Mr M)
Mr M's OCR (not OCR MEI) Core 2 Answers May 2016

1. (i) 10 cm (2 marks)

(ii) 5.04 cm (2 marks)

2. (i) (2 marks)

(ii) (3 marks)

3. (i) (4 marks)

(ii) (2 marks)

4. (i) (2 marks)

(ii) (4 marks)

5. (a) (3 marks)

(b) (i) (4 marks)

(ii) 4 (1 mark)

6. (i) (3 marks)

(ii) (2 marks)

(iii) (6 marks)

7. (i) Quotient and remainder 0 (3 marks)

(ii) or or (3 marks)

(iii) Show (2 marks)

(iv) (4 marks)

8. (i) Translation by 2 units in the positive x direction (2 marks)

(ii) Stretch parallel to the y axis scale factor (2 marks)

(iii) Sketch showing as the only point of intersection (2 marks)

(iv) (3 marks)

(v) 9.60 (3 marks)

9. (i) (1 mark)

(ii) and (3 marks)

(iii) and (4 marks)
How did you get the answer to 9ii?
0
#4
(Original post by bantersaur0usrex)
for 4ii) why was x=-3 not a valid answer?
0
2 years ago
#5
How many marks would be lost if I didn't simplify at the end. I left it as (1/3)/a.

Thanks. How do you think the paper was?
0
2 years ago
#6
For the last question how many marks do you think I would get, I squared everything to get sin^2ax=3cos^2axThen used the identies to get 1-cos^2ax=3cos^2axThen rearranged to get 4cos^2ax=1 ,then cos^2ax=1/4 then square rooted to get cosax=+ or - 1/2Then somehow I ended up with pi/3a and 2pi/3a as my final answer.
Thanks very much
0
#7
(Original post by SGHD26716)
How many marks would be lost if I didn't simplify at the end. I left it as (1/3)/a.

Thanks. How do you think the paper was?
So long as you remembered your pi, you might not lose anything.

I thought it was of standard difficulty.
0
2 years ago
#8
(Original post by Mr M)
1
2 years ago
#9
I made a quadratic out of question 5 bi) and then factorised it, but earlier in my working out had written down the correct answer, do i lose any marks?
1
2 years ago
#10
For the last question 9 iii I left my two answers as (1/3)pi/a and (4/3)pi/a - will I still get the full 4 marks?
0
2 years ago
#11
Do you know what the question was for 4ii? Thanks
0
#12
(Original post by Bobby21231)
For the last question how many marks do you think I would get, I squared everything to get sin^2ax=3cos^2axThen used the identies to get 1-cos^2ax=3cos^2axThen rearranged to get 4cos^2ax=1 ,then cos^2ax=1/4 then square rooted to get cosax=+ or - 1/2Then somehow I ended up with pi/3a and 2pi/3a as my final answer.
Thanks very much
The trouble with squaring is that it can introduce extra incorrect solutions.

2 marks probably.
0
2 years ago
#13
(Original post by Mr M)
Mr M's OCR (not OCR MEI) Core 2 Answers May 2016

1. (i) 10 cm (2 marks)

(ii) 5.04 cm (2 marks)

2. (i) (2 marks)

(ii) (3 marks)

3. (i) (4 marks)

(ii) (2 marks)

4. (i) (2 marks)

(ii) (4 marks)

5. (a) (3 marks)

(b) (i) (4 marks)

(ii) 4 (1 mark)

6. (i) (3 marks)

(ii) (2 marks)

(iii) (6 marks)

7. (i) Quotient and remainder 0 (3 marks)

(ii) or or (3 marks)

(iii) Show (2 marks)

(iv) (4 marks)

8. (i) Translation by 2 units in the positive x direction (2 marks)

(ii) Stretch parallel to the y axis scale factor (2 marks)

(iii) Sketch showing as the only point of intersection (2 marks)

(iv) (3 marks)

(v) 9.60 (3 marks)

9. (i) (1 mark)

(ii) and (3 marks)

(iii) and (4 marks)
How is that the answer to 9ii)?
How did you do 3ii)? (i did 9k^2=1 how many marks would i get?)
0
2 years ago
#14
(Original post by Ozil5)
Do you know what the question was for 4ii? Thanks
2logbase3x - logbase3 (x+4) = 2
0
2 years ago
#15
what was question 6 part i and question 1 exactly. Can't remember the answers that I put. Thanks
0
2 years ago
#16
6iii)
I did the sum of Un and the sum to infinity to Wmn.. and I ended up with 3n^2+17n-1200>0 or 3n^2+17n-1200<0 (i forgotten)... getting n=17.4
Did I do the entire question wrong or do I get any method marks?
0
2 years ago
#17
How did we get a= 5 and k=0 for 9ii ? I think i got a = 5/3 (i think) and k = (√3)/2 or something similar?
0
2 years ago
#18
Thanks sir, for part 5bi. I got the correct answer and wrote it on my exam paper, however for some stupid reason I carried on and made it equal to 0 and tried to solve for a. What will happen here? And for 6iii. I worked it out and got 37.2, but rounded down to 37. How many marks will I get?
0
2 years ago
#19
How is that the answer to 9ii)? I got 5/3=a and k=(root 3)/2

How many marks would i get for 3ii) if i did 9k^2=1 and worked that out to get k=+-1/3
0
2 years ago
#20
(Original post by Mr M)
Here's the graph:

Wasnt the question to find the minimum points on the graph, not the x-intersects?
(Sorry for double posting and sorry if I'm wrong )
0
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