# in desperate need of help

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#1
hi all,

could you please explain to me part c and d in question 10 and question 11.
much appreciated 0
4 years ago
#2
(Original post by penelopecrux)
hi all,

could you please explain to me part c and d in question 10 and question 11.
much appreciated You have the frequency density, can you find the frequency using the class width? (hint: frequency density = frequency / class width so frequency = class width * frequency). Then you can find the midpoint of each histogram bar, for example the first one is (70+80)/2 = 75. Then the mean is sum of (frequency * midpoint) / total frequency.

So it would start as, for the first bar:

class width = 10
midpoint = 75
frequency = 6 * 10 = 60

So frequency * midpoint = (60 * 75).

Then do the same for the second bar, and the third and add all the (frequency * midpoints) up and then divide by the total frequency.
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#3
(Original post by Zacken)
You have the frequency density, can you find the frequency using the class width? (hint: frequency density = frequency / class width so frequency = class width * frequency). Then you can find the midpoint of each histogram bar, for example the first one is (70+80)/2 = 75. Then the mean is sum of (frequency * midpoint) / total frequency.

So it would start as, for the first bar:

class width = 10
midpoint = 75
frequency = 6 * 10 = 60

So frequency * midpoint = (60 * 75).

Then do the same for the second bar, and the third and add all the (frequency * midpoints) up and then divide by the total frequency.
see i did that and i get 100.78125 but the stupid mark scheme says the answer is 75 and i dont know why :/
0
4 years ago
#4
(Original post by penelopecrux)
see i did that and i get 100.78125 but the stupid mark scheme says the answer is 75 and i dont know why :/
Could you post up a picture of your working? Make sure all your frequency numbers are correct, see if they line up with the number on the axes properly, etc...
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#5
(Original post by Zacken)
Could you post up a picture of your working? Make sure all your frequency numbers are correct, see if they line up with the number on the axes properly, etc...
these are my workings out
0
4 years ago
#6
(Original post by penelopecrux)
these are my workings out
I would agree with your answer to part (c) unless I'm missing something blindingly obvious.

For part (d), you know that 288 people passed the test, yes. This means the test score is somewhere in the 130-150 region as the cumulative frequency in that region is 270-320. So now you need to be able to somehow find the test score corresponding to a frequency of 288.
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#7
(Original post by Zacken)
I would agree with your answer to part (c) unless I'm missing something blindingly obvious.

For part (d), you know that 288 people passed the test, yes. This means the test score is somewhere in the 130-150 region as the cumulative frequency in that region is 270-320. So now you need to be able to somehow find the test score corresponding to a frequency of 288.
i got this but i dont think it's right :/
0
4 years ago
#8
(Original post by penelopecrux)
i got this but i dont think it's right :/
Again (it's been a long time since I've done any of this) but I agree with your answer.
0
#9
(Original post by Zacken)
Again (it's been a long time since I've done any of this) but I agree with your answer.
omg thank you so would i do the same thing with the second question?
0
4 years ago
#10
(Original post by penelopecrux)
omg thank you so would i do the same thing with the second question?
Well, not exactly the same thing. You'll want to look up 7.5 on the x-axis and see what the cumulative frequency up to 7.5 is and then do that cumulative frequency / total frequency to find the probability.
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#11
(Original post by Zacken)
Well, not exactly the same thing. You'll want to look up 7.5 on the x-axis and see what the cumulative frequency up to 7.5 is and then do that cumulative frequency / total frequency to find the probability.
i get what you're saying it's just that how can i find the frequency of each bar, im just given one piece of info, so the f.d. would be 9 for the last bar but other than that idk what to do :/
0
4 years ago
#12
(Original post by penelopecrux)
i get what you're saying it's just that how can i find the frequency of each bar, im just given one piece of info, so the f.d. would be 9 for the last bar but other than that idk what to do :/
I think you're on the right track with using the area of squares and stuff.
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