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# Algebraic Fractions help watch

1. I usually know how to do them but now I've started to get a mental block.

What is an easy method to solve them? As well can people help solve these for me so that I get an idea for them myself, thanks.

1) (2x+3)/3 + 4x+1/2 = 43/2
2) (2x+3)/3 + (4x+1)/2 = 43/2x-1
3) (3x+2)/4x-2 + 2/3
2. (Original post by innermight)
I usually know how to do them but now I've started to get a mental block.

What is an easy method to solve them? As well can people help solve these for me so that I get an idea for them myself, thanks.

1) (2x+3)/3 + 4x+1/2 = 43/2
2) (2x+3)/3 + (4x+1)/2 = 43/2x-1
3) (3x+2)/4x-2 + 2/3
get rid of fractions then rearrange and solve for x
3. Multiply both sides of the equation then expand and simplify and all should work out nicely.
4. (Original post by innermight)
I usually know how to do them but now I've started to get a mental block.

What is an easy method to solve them? As well can people help solve these for me so that I get an idea for them myself, thanks.

1) (2x+3)/3 + 4x+1/2 = 43/2
2) (2x+3)/3 + (4x+1)/2 = 43/2x-1
3) (3x+2)/4x-2 + 2/3
Common denominators:

5. (Original post by Zacken)
Common denominators:

So do I leave the = 43/2 untouched?
6. (Original post by innermight)
So do I leave the = 43/2 untouched?
Well, there are multiple ways to do it. You'll end up multiply both sides of the equation by 6 anyhow, so it's not untouched per se.
7. what do you do when they are flipped around??

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